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kvasek [131]
3 years ago
6

Sabrina works at a sporting goods store. She earns $415 per week plus a 5.25% commission on her sales. One week,her sales are 22

00. What is her total income for the week?
Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

530.5

Step-by-step explanation:

=$415(salary)+$2200*5.25%(bones or week plus)

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Answer:B

Step-by-step explanation:

21

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3 years ago
What are variable terms
eduard

Answer:

The following tells what variable terms are and a explanation. I hope this is helpful

Step-by-step explanation:

Each expression is made up of terms. A term can be a signed number, a variable, or a constant multiplied by a variable or variables. ... In , the terms are: 5x, 3y, and 8. When a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.

8 0
3 years ago
A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in​ ft/s. The rang
VARVARA [1.3K]

Answer:

\theta=24.4^\circ

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range​ of a projectile is in reality approximated by the equation x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta), where we will use ft for distances.

From the given equation we have then \frac{x32ft/s^2}{v^2} =sin(2\theta), which means \theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2} since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and  v = 85 ft/s, we can substitute these values from the equation written, and we will have \theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}, and from now on we have just to use a calculator, obtaining \theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ

3 0
3 years ago
Use polar coordinates to find the volume of the given solid. bounded by the paraboloid z = 5 + 2x2 + 2y2 and the plane z = 11 in
podryga [215]
Using cylindrical coordinates,

\displaystyle\int_{x=0}^{x=\sqrt3}\int_{y=0}^{y=\sqrt{3-x^2}}\int_{z=5+2x^2+2y^2}^{z=11}\mathrm dz\,\mathrm dy\,\mathrm dx
\displaystyle=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=\sqrt3}\int_{z=5+2r^2}^{z=11}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\frac\pi2\int_{r=0}^{r=\sqrt3}r(11-(5+2r^2))\,\mathrm dr
=\displaystyle\pi\int_{r=0}^{r=\sqrt3}(3r-r^3)\,\mathrm dr
=\dfrac{9\pi}4
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3 years ago
Chris is reading a book that has 364 pages she reads 3/4 of them then put the book away for a week then she read 3/7 of the rema
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According to my calculations it should be 52 pages
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