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Dmitriy789 [7]
2 years ago
10

HELP! ASAP!

Chemistry
1 answer:
harina [27]2 years ago
8 0

Given the model from the question,

  • The products are: N₂, H₂O and H₂
  • The reactants are: H₂ and NO
  • The limiting reactant is H₂
  • The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

<h3>Balanced equation </h3>

From the model given, we obtained the ffolowing

  • Red => Oxygen
  • Blue => Nitrogen
  • White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

  • Reactants: H₂ and NO
  • Product: N₂, H₂O and H₂

<h3>How to determine the limiting reactant</h3>

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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Salsk061 [2.6K]

The correct answers are as follows:

1. Aluminium will not be useful as food wrapping if it has a much lower melting point.

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2. When bleach react with fabric dye chemical change occur in the fabric.

The major element in bleach is chlorine. When laundry bleach is added to a fabric, the chlorine component of the bleach will react with the fabric dye and cause a colour change in the fabric. This type of change is called chemical change, because the original colour of the fabric can not be recovered.

3. Every substance has specific properties, which can be used to identify it. Two of such specific properties are melting point and boiling point. Melting point refers to a specific temperature at which a solid substance will melt while boiling point refers to a specific temperature at which a liquid substance will boil and turn to steam.

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4 0
3 years ago
How many grams of the excess reactant are left over according to the reaction below given that you start with 10.0 g of Al and 1
valentinak56 [21]
<span>4 Al + 3 O2 → 2 Al2O3 

(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al 
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2 

0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess. 

((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) = 
10.1 g O2 left over</span><span>
</span>
7 0
3 years ago
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Need help with question
3241004551 [841]
C, because a homogeneous mixture is evenly mixed.

All those others would be heterogeneous (not evenly mixed).
5 0
3 years ago
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Which agency publishes the food code
Sergeeva-Olga [200]
Food code is like sort of a guide to ensure that the food is presented according decent standards, unadulterated and correctly presented to the customer.
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4 0
3 years ago
At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)&lt;---&gt;2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an
SOVA2 [1]

<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

                      Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)

<u>Initial:</u>                                                                  0.902

<u>At eqllm:</u>                            3x                           (0.902-3x)

The expression of K_p for above equation follows:

K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}

We are given:

K_p=19.9

Putting values in above equation, we get:

19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0
3 years ago
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