Question

HELP! ASAP!

Answer 1

Given the model from the question,

• The products are: N₂, H₂O and H₂
• The reactants are: H₂ and NO
• The limiting reactant is H₂
• The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

Balanced equation

From the model given, we obtained the ffolowing

• Red => Oxygen
• Blue => Nitrogen
• White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

• Reactants: H₂ and NO
• Product: N₂, H₂O and H₂

How to determine the limiting reactant

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

Learn more about stoichiometry:

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