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valentinak56 [21]
2 years ago
14

Helpp im timed Part A

Chemistry
1 answer:
aksik [14]2 years ago
3 0

Any deviation in the image of an object when light passing from one medium to other is assciated to the phenomenon of refraction.

<h3>What is refraction ?</h3>

It is the deflection from a straight path undergone by a light ray while passing from one medium (such as air) into another (such as glass) in which its velocity is different.


Basically, the light refraction gives the pencil a slight magnifying effect, which makes the angle appear bigger than it actually is, causing the pencil to look crooked.

<h3 />
  • After Looking at the pencil from the side of a clear glass or resealable plastic bag filled three-fourths with water, we will see the light bends around the pencil, causing it to look bent in the water.

  • When the pencil tilt from side to side, It looks so dramatically broken on looking at it from different angles.
    We can magically “fix” the broken pencil by changing where the pencil is positioned in the glass.

Learn more about Light here;
brainly.com/question/22216162

#SPJ1

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A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,
Scorpion4ik [409]

<u>Answer:</u> The value of K_c is coming out to be 0.412

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For Sb_2S_3</u>

Given mass of Sb_2S_3 = 1.00 kg = 1000 g   (Conversion factor: 1 kg = 1000 g)

Molar mass of Sb_2S_3 = 339.7 g/mol

Putting values in equation 1, we get:

\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol

  • <u>For hydrogen sulfide:</u>

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

                  Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)

Initial:            2.944      5

At eqllm:      2.944-x     5-3x         2x        3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}

The expression of K_c for above equation, we get:

K_c=\frac{[H_2S]^3}{[H_2]^3}

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412

Hence, the value of K_c is coming out to be 0.412

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