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Artyom0805 [142]
3 years ago
6

How many molecules are present in 78.9 g of silver nitrate (AGNO3)?

Chemistry
1 answer:
alina1380 [7]3 years ago
8 0

Answer: i will sacrifice my life for pakistan

Explanation:

wow grape

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Brainliest if correct!!!!!
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A

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A paint chip is placed in ethanol and curls what type of paint is it
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A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

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3 years ago
How are silicate minerals different from nonsilicate minerals
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Answer: The main difference between silicate minerals and nonsilicate minerals is that silicate minerals are composed of silicate groups whereas Nonsilicate minerals have no silicate groups.

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