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Kaylis [27]
3 years ago
15

Luis bought two pieces of wax to make candles. One piece weighed 3.49 kg, and the other weighed 4.71 kg. If wax costs $1.80 per

kg, how much did Luis spend altogether?
Mathematics
1 answer:
EleoNora [17]3 years ago
8 0

(3.49+4.71)1.80=cost

(8.2)1.80=cost

14.76=cost

Luis spends $14.76 all together  


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For a recent year, 38 more Democrats than Republicans represented a country. If the total number of representatives of the count
Fantom [35]

Second question isn't well formatted

Answer:

Number of republicans = 207

Number of democrats = 245

Step-by-step explanation:

Let :

Number of republicans = x

Number of democrats = x + 38

Total number of representatives from the two parties = 452

Tge number of representatives from each party can be calculated thus ;

Number of democrats + number of republicans = total number of representatives

(x + 38) + x = 452

x + 38 + x = 452

2x = 452 - 38

2x = 414

x = 414 / 2

x = 207

Number of republicans = 207

Number of democrats = 207 + 38 = 245

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If a diver is 100 feet below the surface, what is the pressure of the water on the diver?
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A man invests $2000 in an account that pays 6.5% interest per year, compounded quarterly.
skelet666 [1.2K]

Answer:

The correct answer is a. $2275.28; b. 17.04 years

Step-by-step explanation:

Principal to be invested is $2000

Interest rate (r) per year is 6.5 quarterly.

Interest is calculated compoundly.

a. Time (t) for the investment is given to be 2 years.

Amount after two years is = Principal × ( 1+ \frac{r}{100n}) ^ {nt} where the value of n is 4.

⇒ A = 2000  × ( 1+ \frac{6.5}{400}) ^ {8}

⇒ A = $2275.28.

b. Now the value of A is given to be triple the principal = $ (3 × 2000).

Therefore we need to find the value of t.

⇒ 3 × 2000 =  2000  × ( 1+ \frac{6.5}{400}) ^ {4t}

⇒ ㏑ 3 = 4t × ㏑ ( 1.01625)

⇒ t = 17.04

Therefore it would take 17.04 years for the principal to triple.

5 0
2 years ago
Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

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