Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
The volume of the Tiny's tank will be equal to V=7760 cubic inches.
<h3>What is volume?</h3>
Volume is defined as the space occupied by any object in the three-Dimensions. All three parameters are required for the volume like length, width and height of the cube and for the cone it will be radius and height.
It is given that:-
The tank is 16 inches tall.
The area of the tank is 485 square inches
So the volume of the tank will be:-
V= πr²h
V=Area x h
V= 485 x 16
V= 7760 cubic inches
Therefore the volume of the Tiny's tank will be equal to V=7760 cubic inches.
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Answer:
≈ 108 m³
Step-by-step explanation:
You're searching for the volume of a cylinder. The formula needed to find it is V=πr²h.
In this case, the radius r is 1.4m and the height h is 35/2=17.5m, as it is only half filled.
Now when inserting values, you get: V=π*1.4²*17.5 which is 107.757 m³
Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.
The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.
So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).