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2 years ago

Simplify 21x^6 y^5 14x^2y^9

Mathematics

1 answer:

PIT_PIT [208]2 years ago

5 0

Answer:

$\frac{3x^{4} }{2y^{4} }$

Step-by-step explanation:

Factor out 7 from top and bottom :

$\frac{7(3x^6y^5)}{7(2x^2y^9)}$

Divide top and bottom by 7 :

$\frac{3x^6y^5}{2x^2y^9}$

Simplify :

$\frac{x^6}{x^4}=x^{2}$

Simplify :

$\frac{y^5}{y^9} = y^{-4} = \frac{1}{y^{4} }$

Collect everything together :

$\frac{3x^{4} }{2y^{4} }$

Hope this helped and have a good day

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What is the rate of change and initial value for the linear relation that includes the points shown in the table? x; 1,3,5,7

BARSIC [14]

Answer:

The rate of change is -5

The initial value is 25

Step-by-step explanation:

Since, this is a linear relation

so, we can select any two points and find equation of line

points are (1,20) and (3,10)

so,

$x_1=1,y_1=20$

$x_2=3,y_2=10$

now, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{10-20}{3-1}$

$m=-5$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

now, we can plug values

$y-20=-5(x-1)$

now, we can solve for y

$y=-5x+25$

we know that

slope is the rate of change

So, the rate of change is -5

For finding initial value , we can plug x=0 and find y

$y=-5\times 0+25$

$y=25$

So, initial value is 25

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Step-by-step explanation:

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Step-by-step explanation:

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