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2 years ago

Simplify 21x^6 y^5 14x^2y^9

Mathematics

1 answer:

PIT_PIT [208]2 years ago

5 0

Answer:

$\frac{3x^{4} }{2y^{4} }$

Step-by-step explanation:

Factor out 7 from top and bottom :

$\frac{7(3x^6y^5)}{7(2x^2y^9)}$

Divide top and bottom by 7 :

$\frac{3x^6y^5}{2x^2y^9}$

Simplify :

$\frac{x^6}{x^4}=x^{2}$

Simplify :

$\frac{y^5}{y^9} = y^{-4} = \frac{1}{y^{4} }$

Collect everything together :

$\frac{3x^{4} }{2y^{4} }$

Hope this helped and have a good day

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18) through: (-3,-3), parallel to y = -x + 3

otez555 [7]

Step-by-step explanation:

y + 3 = - (x + 3)

y + 3 = -x - 3

y = -x - 6

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3 years ago

M<3 is (3x + 4) and m<5 is (2x +11)

butalik [34]

Answer:

Part 1) Option C. Same side interior angles

Part 2) Option A. $(3x+4)+(2x+11)=180\°$

Part 3) Option B. $m$

Step-by-step explanation:

Part 1) we know that

If p and q are parallel

then

m<3 and m<5 are consecutive interior angles or Same side interior angles

and

$m$

Part 2) we know that

$m$ -----> by consecutive interior angles (supplementary angles)

we have that

$m$

substitute

$(3x+4)+(2x+11)=180\°$

Part 3) Find the measure of angle 5

we know that

$(3x+4)+(2x+11)=180\°$

Solve for x

$5x+15\°=180\°$

$5x=180\°-15\°$

$x=165\°/5\°=33\°$

$m$

substitute the value of x

$m$

8 0

3 years ago

Read 2 more answers

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

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3 years ago

The graph of the linear parent function is a ________________ line.

Vadim26 [7]

Answer:

straight ?

Step-by-step explanation:

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3 years ago

How do you simplify 2i<6u ?

marusya05 [52]

In simplifying inequalities, there are a few things that you have to remember. Here are some:

<span>Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own.
But these things will change direction of the inequality:<span>Don't multiply or divide by a variable (unless you know it is always positive or always negative)

We simplify as follows:
2i/2<6u/2
i<3u</span></span>

5 0

3 years ago