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1 year ago

Which equation is equivalent to y−3=4(x−5)?

Mathematics

2 answers:

vlabodo [156]1 year ago

7 0

U solve it as an equation. So u multiply 4 times x and 4 times -5…. U can see how I solved it below

djverab [1.8K]1 year ago

5 0

Answer:

y = 4x - 17

Step-by-step explanation:

y - 3 = 4(x - 5) ← distribute parenthesis by 4

y - 3 = 4x - 20 ( add 3 to both sides )

y = 4x - 17

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In indirect variation if y = 5 and x = 10, what is the value of k (the constant)?

Andre45 [30]

87 the to you do why try ice

4 0

3 years ago

Ashley is taking a road trip to visit her friend. She drives 87.5 miles before taking a break

DanielleElmas [232]

Answer:

112.5

Step-by-step explanation:

200 - 87.5 = 112.5

6 0

2 years ago

The larger of two numbers is five more than twice the smaller number. The sum of the two numbers is 38. Find the numbers.

Damm [24]

Answer:

I would set this up as:

let: lesser number = x

greater number = 2x + 5

Restating the word problem:

lesser number + greater number = 38

x + 2x + 5 = 38

Solving: 3x + 5 = 38

- 5 -5

---------------

3x = 33

--- ---

3 3

x = 11

Substitution for the greater number:

2(11) + 5

22 + 5

8 0

3 years ago

Read 2 more answers

(3x+4)-(-8-2x) simplified

goldenfox [79]

Answer:

5x+12

Step-by-step explanation:

7 0

2 years ago

A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t

Sati [7]

Answer:

$\frac{2}{7}$

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = $\frac{1}{7}$

Remaining fuel after driving around the city = 1 - $\frac{1}{7}$

= $\frac{7 - 1}{7} = \frac{6}{7}$

According to question:

As from the rest of the gas in the car that is $\frac{6}{7}$ , the car can complete 3 trip to Ottawa which means,

By unitary method:

The car can complete 3 trip by using = $\frac{6}{7}$ tank of gas.

The car can complete 1 trip by using = $\frac{6}{7} \div 3$

= $\frac{6}{7} \times\frac{1}{3}$

= $\frac{6}{21}$

= $\frac{2}{7}$ tank of gas

Thus, $\frac{2}{7}$ tank of gas used for each complete trip to Ottawa.

5 0

3 years ago