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1 year ago

Which equation is equivalent to y−3=4(x−5)?

Mathematics

2 answers:

vlabodo [156]1 year ago

7 0

U solve it as an equation. So u multiply 4 times x and 4 times -5…. U can see how I solved it below

djverab [1.8K]1 year ago

5 0

Answer:

y = 4x - 17

Step-by-step explanation:

y - 3 = 4(x - 5) ← distribute parenthesis by 4

y - 3 = 4x - 20 ( add 3 to both sides )

y = 4x - 17

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Name an angle adjacent to ∠DGE. A. ∠FGI B. ∠EGH C. ∠HGJ D. ∠JGI

spin [16.1K]

Answer: Choice B) Angle EGH

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The given angle is DGE. Exactly two of the letters (D, G, and E) will be found in any adjacent angle to this given one. For example, angle FGD is adjacent to DGE because of the shared letters D and G. The two angles share the segment DG.

Similarly, angle DGE is adjacent to EGH for the same reason. Now segment EG is the overlapping shared segment. Note how "E" and "G" can be found in the given angle and the answer.

Edit: see the attached image for visual proof. The given angle is in red. The angle for the answer is in blue.

7 0

3 years ago

What is 1 + 1? answer

Lady bird [3.3K]

Answer:

Step-by-step explanation:

+ 1

hope this helps...

3 0

3 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

3 years ago

Can someone solve this equation -101=7+3(-4t4n)

alex41 [277]

The answer should be n=-8

5 0

3 years ago

Read 2 more answers

Please help me with this

Len [333]

Answer:

60 degrees

Step-by-step explanation:

To first solve this problem, we need to figure out the size of an interior angle for a regular hexagon.

This can be done with the formula :

$angle = \frac{(n-2)*180}{n}$ , with n being the number of sides

A hexagon has 6 sides so here is how we would solve for the interior angle:

$\frac{(6-2)*180}{6}=120$ , with n= 6 sides

Now that we know that each interior angle in the hexagon is 120 degrees, we can now turn our attention to the rhombus.

The opposite angles of the rhombus are congruent, so the two larger obtuse angles are congruent, and so are the two smaller acute angles.

It is also important to note that a rhombus is a quadrilateral, so all of its interior angles add up to 360 degrees.

Looking at the rhombus, we already know one of the angles because it is shared by the interior angle of the hexagon, so the two larger angles in the rhombus are both 120 degrees.

But what about the smaller angles? All we need to do is subtract the two larger angles form 360 and divide by 2 to find the angle.

$\frac{360-2(120)}{2} = 60$ , so the smaller angle in the rhombus is 60 degrees.

Now that we know both the interior angle and smaller angle of the rhombus, we can find x.

Together, angle x and the angle adjacent to it makes up an interior angle of the hexagon, so x plus that angle is going to equal to 120 degrees.

All we need to do is solve for x:

$x+60=120$

$x=120-60$

x = 60 degrees

3 0

2 years ago