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Vika [28.1K]
1 year ago
7

Which equation is equivalent to y−3=4(x−5)?

Mathematics
2 answers:
vlabodo [156]1 year ago
7 0
U solve it as an equation. So u multiply 4 times x and 4 times -5…. U can see how I solved it below

djverab [1.8K]1 year ago
5 0

Answer:

y = 4x - 17

Step-by-step explanation:

y - 3 = 4(x - 5) ← distribute parenthesis by 4

y - 3 = 4x - 20 ( add 3 to both sides )

y = 4x - 17

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What is 10% as a decimal?
DiKsa [7]
Hi there!

10% as a decimal is 0.1

To find the decimal of a percentage, just divide the percentage by 100.

10/100 = 1/10 = 0.1

I hope this helps!
6 0
3 years ago
Help please its math on this test.
Karo-lina-s [1.5K]

Step-by-step explanation:

Fractions with only factors of 2 and 5 are terminating. If not, they give repeating decimals.

Therefore 17/8 and 34/16 are terminating whereas 2/13, 5/24 and 6/7 are repeating decimals.

3 0
3 years ago
A quantity b varies jointly with c and d and inversely with eWhen b is 18, c is 4, d is 9, and e is 6What is the constant of var
777dan777 [17]

Answer:

constant of variation = 3

Step-by-step explanation:

we know that b varies jointly with c and d

so:

b∝c∝d

and b varies inversely with e, so

b∝\frac{1}{e}

and i will call the constant of variation k, this way we can make an equation for b in the following form:

b=k\frac{cd}{e}

this satisfy that b varies jointly with c and d (if b increases, c and d also increase) and inversely with e (if b increases, e decreases)

we know that when b is 18, c is 4, d is 9, and e is 6:

b=18\\c=4\\d=9\\e=6

substituting this in our equation for b:

b=k\frac{cd}{e}\\ 18=k\frac{(4)(9)}{6}

and we solve operations and clear for the constant of variation k:

18=k\frac{36}{6}\\ 18=6k\\\frac{18}{6}=k\\ 3=k

the constant of variation is 3.

4 0
3 years ago
Read 2 more answers
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
Solve for x.<br><br><br><br> 80<br> 22<br> 40<br> 12
kari74 [83]
Use the Pythagorean theorem to solve this problem. So, 81+x^2=1681. ( Pythagorean theorem: a^2+b^2=c^2). x^2=1600. x=40.
4 0
3 years ago
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