602,107.
Six hundred and two thousand and one hundred and seven.
I hope this helps!
The answer to your problem would be 10.
if two figures are congruent, each side is congruent to the same side on the other figure.
AB=FG; CD=HI; EA=JF
since CD=HI, and CD=10, then HI would also equal 10
Answer:
Step-by-step explanation:
2
(
2
x
−
1
)
+
7
<
13
Expand LHS
→
4
x
−
2
+
7
<
13
4
x
+
5
<
13
4
x
<
13
−
5
4
x
<
8
Divide through by
4
→
x
<
2
x
<
2
is represented on the real line by the interval
(
−
∞
,
2
)
This can be represented on the
x
y
−
plane by the area to the left of the vertical line
x
=
2
as graph below.
graph{2(2x-1)+7<13 [-10, 10, -5, 5]}
Answer:
II
Step-by-step explanation:
All the other options create a number that is smaller than 7, while the inequality suggests otherwise.
While, II create the number 9 - which is indeed bigger then 7
Glad to help ÷)
The first thing we are going to do is rewrite the expression correctly.
We have:
root (27x ^ 12 / 300x ^ 8)
Rewriting:
root ((27/300) * (x ^ 12 / x ^ 8))
root ((9/100) * (x ^ (12-8)))
root ((9/100) * (x ^ (4)))
root ((9/100) * (x ^ (4)))
3 * x ^ 2 * root ((1/100)
(3 * x ^ 2) / 10
(3/10) * (x ^ 2)
Answer:
(3/10) * (x ^ 2)
