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3 years ago

Is the function cot t positive or negative in Quadrant II?

2 answers:

6 0

Cotangent and Tangent in the Second Quadrant are negative

Only can find cot and tan positive in the First and Third Quadrant

artcher [175]3 years ago

4 0

Graph is divided into four quadrants .The axes of a two-dimensional Cartesian system divide the plane into four infinite regions, called quadrants, each bounded by two half-axes . These are often numbered from 1st to 4th and denoted by Roman numerals

The question is asking us to find the sign of cot in quadrant II.

In quadrant II the Trigonometry functions sine and cosecant are positive other that is cos ,tan ,secant and cot are negative.

The function cot is negative in Quadrant II.

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Find the 10th term of an arithmetic sequence if the common difference is 32 and the first term is 2

zaharov [31]

Answer:

290

Step-by-step explanation:

If the first term is 2 and the common difference is 32, then the formula for a(n) is:

a(n) = 2 + 32(n-1).

Thus, the 10th term is a(10) = 2 + 32(10-1) = 2 + 32(9) = 290

6 0

3 years ago

Homework help, please

Vinvika [58]

Start the line at 3 on the y-axis (vertical). then go down two boxes and to the right three & make a mark at that point. keep going down two and over three until the end of the graph. then just connect the marks.

4 0

2 years ago

In one day, the stock price for Warbucks Coffee rose from $50 to $57 per share. By what percent did this stock price rise?

egoroff_w [7]

Answer:

14%

Step-by-step explanation:

1. The formula to find percent change is $\frac{(V_2-V_1)}{|V_1|} * 100$ . Now, all we have to do is plug in the values to their corresponding variable.

2. (Solving)

$\frac{(57-50)}{|50|} * 100$
$\frac{7}{50} *100$

$0.14 * 100$
14%

7 0

2 years ago

The matrix C=[1,-2_-3,7] was used to encode a phrase to [7,-28,-25,-35,-2_-21,107,90,123,17]. Find C^-1 and use it to decode the

posledela

$C= \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right] \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right] \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]$
is the required matrix.

6 0

2 years ago

Simplify: ( 6 to the second power minius 7 times 3 ) + 3 cubed

Tju [1.3M]

Answer:

Step-by-step explanation:

6 to the second power minius 7 times 3 is 15 then with is cubed it would be 42

5 0

3 years ago