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statuscvo [17]
2 years ago
7

Triangle N P O is shown. Line O N extends through point M to form exterior angle P N M. Angle N P O is 38 degrees. Angle P O N i

s 39 degrees. Exterior angle P N M is x degrees.
Which statement about the value of x is true?
x > 38
x < 39
x < 77
x > 103
Mathematics
1 answer:
elixir [45]2 years ago
6 0

The measure of the exterior angle PNM will be x < 77. Then the correct option is C.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

Triangle NPO is shown.

Line ON extends through point M to form exterior angle PNM.

Angle NPO is 38 degrees.

Angle PON is 39 degrees.

Let the exterior angle PNM is x degrees and the interior angle PYO be y.  

Then we have

38 + 39 + y = 180°

                y = 103°

And we know that the sum of interior and exterior angle is a triangle is 180 degrees.

   x + y < 180

103 + x < 180

         x < 77

Then the correct option is C.

More about the triangle link is given below.

brainly.com/question/25813512

#SPJ1

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Answer:

a. C= 5/9(F-32)

Step-by-step explanation:

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2 years ago
Two quantities, Pand Q, are connected by
frez [133]

Answer:

P = 0.5Q - 20

Step-by-step explanation:

P = kQ + c

substitute Q = 60 , P = 10 into the equation

10 = 60k + c → (1)

substitute Q = 240, P = 100 into the equation

100 = 240k + c → (2)

subtract (1) from (2) term by term to eliminate c

90 = 180k ( divide both sides by 180 )

\frac{90}{180} = \frac{1}{2} = 0.5 = k

substitute k = 0.5 into (1) and solve for c

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10 = 30 + c ( subtract 30 from both sides )

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P = 0.5Q - 20

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2 years ago
What is 'Five less than 25' in numerical expression?
saveliy_v [14]

Answer:

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7 0
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A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

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2 years ago
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