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jenyasd209 [6]
3 years ago
14

Each dance class is 3/4 hour it takes a student 7 1/2 hours to learn a dance routine which statement is true a (a) student needs

to take a 6 dance class to learn the routine) (b) student needs to take five dance classes to learn this routine see a student needs to take 9 dance classes to learn the routine) or (d) a student needs to take 10 dance classes to learn the routine)
Mathematics
2 answers:
inysia [295]3 years ago
8 0
7 1/2 divided by 3.4 = 10. 
The student will need 10 dance classes to learn the routine. Hope it helps! :)
Charra [1.4K]3 years ago
6 0

Answer:  The correct option is (d) a student needs to take 10 dance classes to learn the routine.

Step-by-step explanation:  Given that each dance class is \dfrac{3}{4} hour and a student takes 7\dfrac{1}{2} hours to learn a dance routine.

We are to select the TRUE statement.

Duration of each dance class is given by

t_d=\dfrac{3}{4}~\textup{hours},

and the time taken by a student to learn a dance routine is given by

t_s=7\dfrac{1}{2}=\dfrac{15}{2}~\textup{hours}.

Therefore, the number of dance class that a students needs to learn the dance routine will be

n=\dfrac{t_s}{t_d}=\dfrac{\frac{15}{2}}{\frac{3}{4}}=\dfrac{15}{2}\times\dfrac{4}{3}=10.

Thus, a student needs 10 dance classes to learn the dance routine.

Option (d) is CORRECT.

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Nora's paper airplane flew 9 1/6 feet. That was 2 3/4 feet farther than Max's plane flew. Write and solve an equation to show ho
stepan [7]

Answer:

Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

Step-by-step explanation:

As Nora's paper airplane flew 9 1/6 feet

i.e.

9\frac{1}{6}=\frac{55}{6}

Nora's paper was farther than Max's plane flew by = 2 3/4 feet

i.e.

2\frac{3}{4}=\frac{11}{4}

Thus the equation to show how far Max's paper airplane flew is:

\:\:9\frac{1}{6}-2\frac{3}{4}

=\frac{55}{6}-\frac{11}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}6,\:4:\quad 12

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

=\frac{110}{12}-\frac{33}{12}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{110-33}{12}

\mathrm{Subtract\:the\:numbers:}\:110-33=77

=\frac{77}{12}

=6\frac{5}{12}

Therefore, Max's paper airplane flew \frac{77}{12} feet or 6\frac{5}{12} feet.

6 0
3 years ago
Write an equation of the line with a slope of -2/7 and y intercept of 5
sesenic [268]

Answer:

y = -2/7+5

Step-by-step explanation:

Hope this helps!

8 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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The length is not provided and need to find the shaded area
earnstyle [38]

Answer:

The Area of Shaded region is 98 square inch

Step-by-step explanation:

In this given figure

length = 8 in = 3 + x

breadth = 4 + y

In a Rectangle

a shape with four straight sides and four angles of 90 degrees (right angles). Two of the sides are longer than the other two

Now, let the smaller side be x and bigger side be y

Here, we get the equation

x + 3 = 8

x + 3 - 3 = 8 - 3

x = 5

Here, we get the value of x is 5

Now, By Pythagoras Theorem

x² + y² = 13²

(5)² + y² = 169 (x = 5)

25 + y² = 169

y² + 25 - 25 = 169 - 25

y² = 144

√y² = √144

y = 12

So, breadth = 4 + 12 = 16 inch

Now, For the area of rectangle

A = l × b

A = 8 × 16 in

A = 128 square inch

In a given triangle,

b = y = 12 in

h = x = 5 in

Now, For the area of Triangle

<em>A = ½ × b × </em><em>h</em>

A = ½ × 12 × 5 in

A = 6 × 5 in

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So, For the shaded area,

= Area of Rectangle - Area of triangle

= 128 - 30

= 98 square inch

Thus, The Area of Shaded region is 98 square inch

<u>-</u><u>TheUnknownScientist</u>

3 0
3 years ago
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