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nikdorinn [45]
3 years ago
14

Mary creates a table of values for a function and plots the points. She finds that the difference in the y values is the same. W

hat kind of function did she graph? a. linear b. quadratic c. square root d. exponential
Mathematics
2 answers:
Lilit [14]3 years ago
5 0

Answer:

Answer is: A(Linear)

Step-by-step explanation:

A linear function is a function whose graph is a straight line.

It is given that Mary plotted a graph and she found out that the difference in the y values is the same. So such a thing could happen when a function is a linear function.

since, a linear equation is given as:

y=ax+b where a and b are real numbers.

so for distinct values of x say x_{1},x_{2} we get the y-values as y_{1},y_{2}

now,

y_{1}-y_{2}=a(x_{1}-x_{2})

so for equally spaced x_{i}'s we get the difference in y-value to be equal.

Hence, the function is Linear.



uysha [10]3 years ago
4 0
"a. linear" is the answer.

Since the difference between each of the y values, which are the outputs, are the same, it must mean that Mary would've gotten a straight line if she graphed this function. Thus, it is a linear function.
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Georgia ,a florist,charges $10 per flower bundle plus a$15 delivery charge per order what is the slopes​
andrew11 [14]

Answer:

  • <em><u>The slope is $ 10 per flower bundle.</u></em>

Explanation:

The <em>slope</em> of a linear function is the ratio of the change in the dependent variable over the change in the independent variable.

In the problem, the independent variable is the number of flower bundles and the dependent variable is the amount charged.

If you call n the number of flower bundles and c(n) the amount charged per order, the amount charged per order is modeled by linear function:

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Where, 10 is the amount charged in dolars per flower bundle, and 15 is the delivery charge per order.

Then, for every increment in the number of flower bundles (n) the amount charged will increase in $ 10. That is the slope

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3 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

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