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maks197457 [2]
2 years ago
11

A certain 90-mile trip took 2 hours. Exactly 1/3 of the distance traveled was by rail and this part of the trip took 1/5 of the

travel time. What was the average rate, in miles per hour, of the rail portion of the trip?
A. 71 B. 73 C. 74 D. 75
Mathematics
1 answer:
antiseptic1488 [7]2 years ago
7 0

The average rate, in miles per hour, of the rail portion of the trip is; D: 75

<h3>How to calculate the average speed?</h3>

Since exactly 1/3 of the distance travelled was by rail, then we can say that;

(1/3) * (90) = 30 miles

We are told that part of the trip took 1/5 of the travel time. Thus;

Time it takes to travel that distance is:

(1/5) * (2) = 2/5 of an hour

Average rate is;

30/(2/5) = 150/2 = 75 mph

Read more about Average speed at; brainly.com/question/4931057

#SPJ1

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Linda bought a total of 12 lb of flounder and shrimp and paid $20 for the flounder and $20 for the shrimp. If the price per poun
d1i1m1o1n [39]

Answer:

B: 4 lb shrimp and 8 lb flounder

Step-by-step explanation:

if the price of shrimp is twice the price for flounder, you will have twice as much flounder as you have shrimp, so in terms the only answer that applies to this is B.

8 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
Simplify each expression by using the Distributive Property and combine like terms to simplify the expression.-2(-x-1)-(x+9)
Ymorist [56]

-2(-x-1)-(x+9)

= -2x + 2 - x - 9

Rearrange

= -2x - x + 2 - 9

= -3x - 7

8 0
1 year ago
If the current temperature is -11°F, what change in temperature would result in a final temperature of -27°F?
kirill [66]
-7 F I think is the answers
4 0
3 years ago
10 - 3*3 / 9 = ?<br><br> * = to the power of<br><br> / = divided by
Neporo4naja [7]

Answer:

7

Step-by-step explanation:

you need to use PEMDAS

3 x 3 x 3 = 27 divided by 9 is 3 and 10-3=7

6 0
3 years ago
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