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maks197457 [2]
2 years ago
11

A certain 90-mile trip took 2 hours. Exactly 1/3 of the distance traveled was by rail and this part of the trip took 1/5 of the

travel time. What was the average rate, in miles per hour, of the rail portion of the trip?
A. 71 B. 73 C. 74 D. 75
Mathematics
1 answer:
antiseptic1488 [7]2 years ago
7 0

The average rate, in miles per hour, of the rail portion of the trip is; D: 75

<h3>How to calculate the average speed?</h3>

Since exactly 1/3 of the distance travelled was by rail, then we can say that;

(1/3) * (90) = 30 miles

We are told that part of the trip took 1/5 of the travel time. Thus;

Time it takes to travel that distance is:

(1/5) * (2) = 2/5 of an hour

Average rate is;

30/(2/5) = 150/2 = 75 mph

Read more about Average speed at; brainly.com/question/4931057

#SPJ1

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Use Green's Theorem to evaluate the line integral along the given positively oriented curve.
FromTheMoon [43]

Answer:

∫ C ( y + e√x) dx  +  ( 2x + cosy² ) dy = 1/3

Step-by-step explanation: See Annex

Green Theorem establishes:

∫C ( Mdx  +  Ndy )  = ∫∫R ( δN/dx  -  δM/dy ) dA

Then

∫ C ( y + e√x) dx  +  ( 2x + cosy² ) dy

Here

M = 2x  + cosy²           δM/dy  =  1

N = y + e√x                 δN/dx  =  2

δN/dx  -  δM/dy  =  2  -  1   = 1

∫∫(R) dxdy   ∫∫ dxdy

Now integration limits  ( see Annex)

dy  is from   x  = y²    then     y = √x    to  y = x²   and for dx

dx   is from 0   to  1 then

∫ dy    = y | √x   ;   x²      ∫dy    =  x² - √x

And

∫₀¹ ( x² - √x ) dx    =  x³/3  - 2/3 √x |₀¹    =   1/3 - 0

∫ C ( y + e√x) dx  +  ( 2x + cosy² ) dy = 1/3

5 0
3 years ago
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xxTIMURxx [149]

Answer:

1. MIGHT be 16 1/2

Step-by-step explanation:

causse 2/3 / 4/9 = 1 1/2

1 1/2 + 10= 11 +5 = 16

16+1/2 = 16 1/2

4 0
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Answer:

C) -1.5 < -0.5

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1. Is 8 seconds
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5. The expected weight must be greater or equal to 20 pounds but less than 32 pounds.
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Answer:

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6 0
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