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Roman55 [17]
2 years ago
13

Angelina's family owns a mini-golf course. When discussing the business with a customer, she explains there is a relationship be

tween the number of visitors and
hole-in-one winners. If x is the number of visitors and y is the number of winners, which conclusion is correct?
A. The ordered pair (-3, 6) is viable.
B. The ordered pair (7, 2) is viable.
C. The ordered pair (15,-7) is viable.
D. The ordered pair (18,3) in non viable
Mathematics
1 answer:
Mrrafil [7]2 years ago
7 0

The ordered pair (7,2) is viable and Option B is the correct answer.

<h3>What is Relationship ?</h3>

Relationship between variables defines the way one variable is dependent upon the other variable.

It is given that x is the number of visitors and y is the number of winners,

It has to be seen and chosen that which ordered pair makes sense

The ordered pair is viable if the no. of visitor is positive and more than the number of winners.

Therefore ordered pair (7,2) is viable and Option B is the correct answer.

To know more about Relationship

brainly.com/question/14389660

#SPJ1

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Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

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99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

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