Answer:
(4x + 7y)(4x - 7y)
Step-by-step explanation:
Rewrite 16 as 4^2
= 4^2x^2 - 49y^2
Rewrite 49 as 7^2
= 4^2x^2 - 7^2y^2
Apply the Exponent Rule Pt 1 ((a^m*b^m =(ab)^m))
= (4x)^2 - 7^2y^2
Apply the Exponent Rule Pt 2
= (4x)^2 - (7y)^2
Apply Difference of Squares Formula (( x^2-y^2 = (x + y)(x - y)
= (4x + 7y) (4x - 7y)
Answer:
Sorry, I can't type well.
Here’s an explanation! let me know if you need further clarification
You can do 1-1/6 (1 represents the whole class)
6/6-1/6
=5/6
<h3>Answer: Since the independent variable x is not the exponent, y = 3x^3 is <u>not</u> an exponential function (choice D)</h3>
Exponential functions are something like y = 2^x where the variable is in the exponent (ie the exponent isnt a fixed number). What is given here, y = 3x^3, is a cubic function. You can also call this a power function. Power functions are of the form a*x^b, where a & b are constants.
