All categories

3 years ago

Which is the solution set of 6x^2-24=0○(-2,2)○(-2)○(2)

Mathematics

1 answer:

Katarina [22]3 years ago

4 0

Rewrite <span>6x^2-24=0 as 6(x^2-4)= 0 and then factor x^2-4:

6(x-2)(x+2)= 0. The solutions are {-2,2}.</span>

You might be interested in

Help me with this question if you don’t mind

vampirchik [111]

Answer:

Step-by-step explanation:

if AB is congruent to AC that means both are 76 degrees so subtract that from the total degrees of a whole triangle which is 180 that gives you A which is 28.

Hope it helps :)

5 0

3 years ago

Solve the inequality.<br> 140 < -20j

klemol [59]

Answer:

J < -7

Explantion:

Rewrite so J is on the left side

-20j > 140

Divide each term by -20 and simplify

j < -7

8 0

3 years ago

A store buys an item for $10. To earn a PROFIT of $25, what percent does 13 po

LuckyWell [14K]

Answer:

150%

Step-by-step explanation:

25-10= 15

15/10 = 1.5

1.5 = 150%

6 0

3 years ago

Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul

umka21 [38]

Answer:

The number of calculators is 4871

Step-by-step explanation:

If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.

$x=\int\limits^5_3 {\frac{dx}{dt}} \, dt =\int\limits^5_3 {5000(1-\frac{100}{(t+10)^2})} \, dt$

the result of the integration is:

$x=5000(t+\frac{100}{t+10})$ to be evaluated between 3 and 5, which is:

$x=5000(5+\frac{100}{5+10})-5000(3+\frac{100}{3+10})=\frac{190000}{39}=4871.8$

6 0

3 years ago

A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.

a_sh-v [17]

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:

$A=Lw$

We can use the relationship given in the problem, that is, its length being five less two times its width, that is:

$L=5-2w$

Replacing in the formula for the area we get:

$A=(5-2w)w$

Now we use the distributive law:

$A=5w-2w^2$

7 0

1 year ago