Answer: I don’t think there is such a line. A Line that passes through the point (3,-9) must have a positive slope, unlike the line y=-5x-2, which has a negative slope. If a line where to go through (3,-9), is would intersect the line you presented.
Answer:
$y=(7/2)x+20$
Step-by-step explanation:
SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.
Therefore by the point slope formula the line that we are looking for is
$y-6=(7/2)(x+4)$
$y=(7/2)x + 20$
Answer:
Step-by-step explanation:
Answer:
364.
Step-by-step explanation:
14C3 = 14! / 11! 3! which simplifies to:
14*13*12 /3*2*1
= 14*13* 2
= 364.
