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VikaD [51]
2 years ago
6

Plot all ordered pairs for the values in the domain D: (-8, -4, 0, 2, 6)

Mathematics
1 answer:
alexdok [17]2 years ago
3 0

All ordered pairs for the values in the domain will be (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).

<h3>What is coordinate geometry?</h3>

Coordinate geometry is the study of geometry using the points in space.

The function is given below.

y = (1/2) x + 1

Then the domain is D: (-8, -4, 0, 2, 6)

Then the ordered pair will be

For x = -8

y = (1/2)(-8) + 1

y = -3

For x = -4

y = (1/2)(-4) + 1

y = -1

For x = 0

y = (1/2)(0) + 1

y = 1

For x = 2

y = (1/2)(2) + 1

y = 2

For x = 6

y = (1/2)(6) + 1

y = 4

All ordered pairs for the values in the domain will be (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).

More about the coordinate geometry link is given below.

brainly.com/question/1601567

#SPJ1

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mrs_skeptik [129]

Answer:

The coefficient of variation for <em>A</em> is 24.6%.

The coefficient of variation for <em>B</em> is 33.7%.

Step-by-step explanation:

The coefficient of variation (<em>CV</em>) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.

The formula to compute the coefficient of variation is,

CV=\frac{SD}{Mean}\times 100\%

Consider the data set <em>A.</em>

Compute the mean of the data set <em>A </em>as follows:

Mean_{A}=\frac{1}{n}\sum X

            =\frac{1}{14}\times [36900+19400+...+26000+38400]\\=30064.2857

Compute the standard deviation of the data set <em>A </em>as follows:

SD_{A}= \sqrt{ \frac{ \sum{\left(x_i - Mean_{A}\right)^2 }}{n-1} }

        = \sqrt{ \frac{ 712852142.8571 }{ 14 - 1} } \\\approx 7405.051

Compute the coefficient of variation for <em>A</em> as follows:

CV=\frac{SD_{A}}{Mean_{A}}\times 100\%

      =\frac{7405.051}{30064.2857}\times 100\%\\=24.6\%

The coefficient of variation for <em>A</em> is 24.6%.

Consider the data set <em>B.</em>

Compute the mean of the data set <em>B </em>as follows:

Mean_{B}=\frac{1}{n}\sum X

            =\frac{1}{11}\times [2.1+5.0+...+4.1+1.7]\\=3.2455

Compute the standard deviation of the data set <em>B </em>as follows:

SD_{B}= \sqrt{ \frac{ \sum{\left(x_i - Mean_{B}\right)^2 }}{n-1} }

        = \sqrt{ \frac{ 11.9873 }{ 11 - 1} } \\\approx 1.0949

Compute the coefficient of variation for <em>B</em> as follows:

CV=\frac{SD_{B}}{Mean_{B}}\times 100\%

      =\frac{1.0949}{3.2455}\times 100\%\\=33.7\%

The coefficient of variation for <em>B</em> is 33.7%.

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3 years ago
A kite needs to be flown at a height 45 feet in the air. The kite's string will be attached to a pole, at a point 5 feet above t
Nastasia [14]

The length of the rope is approximately 56.57 feet.

Here, Kite's position is at point A which is 45 ft above the ground.

So, in the diagram AC= 45 ft.

B is the point on the pole above 5 ft. from ground, where the kite's string will be attached. So, BD= 5 ft

In the diagram, we will draw a line from point B parallel to the ground which will meet the line AC at point E.

As, BD= 5 ft, so EC= 5 ft also. Now, AE= AC - EC = 45- 5 = 40 ft.

The angle of elevation of the string from the kite's position is 45°

For that, ∠ABE = 45° also (according to the Alternate Interior Angles)

So, in right angle triangle ABE,

in respect of ∠ABE, opposite side(AE)= 40 and we need to find the length of the rope, which is hypotenuse AB.

As, Cosθ = \frac{opposite}{hypotenuse}

So, in ΔABE,

Cos(45°) = \frac{AE}{AB}

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⇒ AB = \frac{80}{\sqrt{2}}  = \frac{80\sqrt{2}}{2} (multiplying up and down by √2)

⇒ AB = 40√2 = 56.57 (approximately)

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