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VikaD [51]
2 years ago
6

Plot all ordered pairs for the values in the domain D: (-8, -4, 0, 2, 6)

Mathematics
1 answer:
alexdok [17]2 years ago
3 0

All ordered pairs for the values in the domain will be (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).

<h3>What is coordinate geometry?</h3>

Coordinate geometry is the study of geometry using the points in space.

The function is given below.

y = (1/2) x + 1

Then the domain is D: (-8, -4, 0, 2, 6)

Then the ordered pair will be

For x = -8

y = (1/2)(-8) + 1

y = -3

For x = -4

y = (1/2)(-4) + 1

y = -1

For x = 0

y = (1/2)(0) + 1

y = 1

For x = 2

y = (1/2)(2) + 1

y = 2

For x = 6

y = (1/2)(6) + 1

y = 4

All ordered pairs for the values in the domain will be (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).

More about the coordinate geometry link is given below.

brainly.com/question/1601567

#SPJ1

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Natalka [10]

None of these. All of these functions are defined as ratio of trigonometric functions.

Trigonometric functions have infinite zeroes, so when you put them in the denominator, they lead to infinitely many points of ill-definition.

Specifically, we have:

\csc(x) = \dfrac{1}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

\sec(x) = \dfrac{1}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\tan(x) = \dfrac{\sin(x)}{\cos(x)}

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\cot(x) = \dfrac{\cos(x)}{\sin(x)}

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4 0
3 years ago
Desmond deposits $50 into a savings account every month at an annual interest rate of
joja [24]

Given:

Desmond deposits $ 50 monthly.

Yearly he deposits = $50×12 = $ 600

Rate of interest compounded monthly = 4.7%

To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.

Formula

A = P(1+\frac{r}{(n)(100)} )^{nt}

where,

A be the final amount

P be the principal

r be the rate of interest

t be the time and

n be the number of times the interest is compounded.

Now,

Taking,

P = 600, r = 4.7, n = 12, t = 10 we get,

A = 600(1+\frac{4.7}{(12)(100)}) ^{(12)(10)}

or, A = 600(1.0039)^{120}

or, A = 959.1

Now,

At starting he has $ 600

At the end of 10 years he will be having $ 959.1

So,

The amount of change in his account = $ (959.1-600) = $ 359.1

Therefore the rate of change = (\frac{359.1}{600} )(100) %

= 59.85%

Hence,

a) His account will contain $ 959.1 after 10 years.

b) The rate of change in his account is 59.85% after 10 years.

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Answer:

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Step-by-step explanation:

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