To answer the question above, we have to use the z-score percentile table for the standard normal distribution. It shows:
The 20th percentile = - 0.84
The 40th percentile = - 0.25
The 60th percentile = 0.25
The 80th percentile = 0.84
I hope my answer helped you. Have a nice day!
Answer:
64 ivy stems
Step-by-step explanation:
To solve this problem we can use rule of three:
Firstly we had 72 ivy stems to use in 18 centerpieces, and know we have 16 centerpieces and want to know how many ivy stems we need to use, so:
18 centerpieces -> 72 ivy stems
16 centerpieces -> X ivy stems
18/16 = 72/X
X = 16*72/18 = 64
He needs to use now 64 ivy stems to maintain the ratio.
Answer:
b =-2
Step-by-step explanation:
-3b+7=13
Subtract 7 from each side
-3b+7-7=13-7
-3b = 6
Divide each side by -3
-3b/-3 = 6/-3
b = -2
Answer:
1. P(S) = 373/580
2. P(S|A) = 53/116
3. P(S|Pa) = 481/580
Step-by-step explanation:
Given
---------------------Sale ----- No Sale-----Total
Aggressive ----265 --------315 ----------580
Passive ----------481 ---------99 -----------580
Total --------------746---------414------------1160
A = aggressive approach,
Pa = passive approach,
S = sale,
N= no sale.
(a) Computing P(S)
This is calculated as the division of customers that participated in sales by total customers
Customers that participated in sales = 265 + 481 = 746
Total Customers = 1160
P(S) = 746/1160
P(S) = 373/580
b.
P(S|A) means that the probability that a sales occur given that the aggressive method was used.
To solve this, we check the cell where Sales and Aggressive intersect
The cell element = 265
Total = 580
P(S|A) = 265/580
P(S|A) = 265/580
P(S|A) = 53/116
c.
P(S|Pa) means that the probability that a sales occur given that the passive method was used.
To solve this, we check the cell where Sales and Passive intersect
The cell element = 481
Total = 580
P(S|Pa) = 481/580