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3 years ago

7

What is the slope-intercept form of the linear equation 2x + 3y = 6? Drag and drop the appropriate number, symbol, or variable t

o each box.

2 answers:

aev [14]3 years ago

5 0

Answer:

$y=-\frac{2}{3}x+2$

Step-by-step explanation:

y = -2/3 x + 2

user100 [1]3 years ago

4 0

Answer:y=-2/3x+2

Step-by-step explanation:

Trust me

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What is the sum of 90 minutes and 50 minutes? 130 minutes 1 hour, 40 minutes 2 hours 2 hours, 20 minutes

LiRa [457]

90 mins + 50 mins = 140 mins
60 mins ==1 hr 2*60 = 120 mins
140 mins -120 mins= 20 mins
2 hrs ans 20 mins is the answer

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3 years ago

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slavikrds [6]

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rusak2 [61]

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2 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

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3 years ago

What is 47.2 % of 300 ?

kupik [55]

For this type of question, you just need to multiply the percentage with the number
so, the calculation would be

47.2% x 300

47.2/100 x 300

47.2 x 3

= 141.6

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3 years ago

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