Question

8.3.4 Karl bought five folders from Pay-A-Lot at a cost of $2.50 each. Pay-A-Lot had a 20% -off sale the following day. How much could Karl have saved on the purchase by waiting a day?

Answer 1

Answer:

Karl could have saved $2.50

Step-by-step explanation:

Cost of folders without the sale: 2.5*5 = $12.50

Cost of folders with the sale: 0.8*2.5 = $2 per folder * 5 folders = $10.00

Difference between prices: 12.5-10 = $2.50

Answer 2

Answer:

2.50$ Karl could have saved on the purchase by waiting a day.

Step-by-step explanation:

Given: total number of folders Karl bought is 5 .

The cost of each folder is 2.50$.

20% off sale the following day at Pay-A-Lot.

we have to find the 20% of each folder and then add them to get the final saving of Karl if he had waited for a day.

Step 1 of 2

20% of 2.50$ is equal to

$\begin{aligned}&=2.50 \cdot 20 \% \\&=2.50 \cdot \frac{20}{100} \\&=0.50 \ \end{aligned}$

this is the amount Karl would save on each folder if waited for a day or this is the discount on the amount of 2.50$ that the shopkeeper will give the next day on each

Step 2 of 2

Karl bought 5 folders

so, total savings would be equal to

$\begin{aligned}&=5 \cdot 0.50 \\&=2.50 \ \end{aligned}$