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2 years ago

Tan + Cos / 1 + Sin = Sec

1 answer:

7 0

$\tan x+\frac{\cos x}{1+\sin x}\\\\ =\frac{\sin x}{\cos x}+\frac{\cos x}{1+\sin x}\\\\=\frac{\sin x(1+\sin x)+\cos^{2} x}{\cos x(1+\sin x)}\\\\=\frac{\sin^{2} x+\cos^{2} x+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1}{\cos x}\\\\=\sec x$

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Write the rules for determining the sign of the product when multiplying integers. Then, write (4 points)

borishaifa [10]

While multiplying a negative and another negative integer, the product's will be positive. While multiplying a positive and another positive integer, the product will be positive. It means that of the integers have same sign, then their product's sign will be positive. But, if the integers have different signs, i.e., one of them is positive and the other is negative, then the product will have negative sign.

While dividing a negative from another negative integer, the quotient will be positive. While dividing a positive from another positive integer, the quotient will be positive. It means that of the integers have same sign, then their quotient's sign will be positive. But, if the integers have different signs, i.e., one of them is positive and the other is negative, then the quotient will have negative sign.

6 0

3 years ago

Read 2 more answers

Need help pls and thank you

jenyasd209 [6]

Answer:

105 cm^3.

Step-by-step explanation:

Its volume = area of triangular side * length

= 1/2 * 5 * 7 * 6

= 105 cm^3.

5 0

3 years ago

Pls help me:) A-(4•7)^-4 B-1/28^2 C-7^-2/4^2 D-(4•7)^4

Sergio039 [100]

Answer:

$\frac{1}{(28)^{2} }$

Step-by-step explanation:

Step 1;

Write expression

$4^{-2} . 7^{-2\\\frac{\frac{1}{4^{-2} } }{y\frac{1}{7^{-2} } } }$

$\frac{1}{4^{2} .7^{2} }$

$\frac{1}{(4x7)^{2} }$

$\frac{1}{(28)^{2} }$

8 0

3 years ago

Explain how to use the combine place values strategy to find 223-119

Vikentia [17]

So, the subtraction looks like this:

   223
-119
_______

The reason why combining place values here is necessary is that 3 is less than 9 (so I can't just substract in the one's place without going to negative numbers)

so we combine the ones and tens places and substract the whole: 23-19 is four!
   223
-119
_______
   04

and then we continue
   223
-119
_______
    204

and that's the result!

3 0

3 years ago

Read 2 more answers

Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%

Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

n = 10

Compute the sample mean and sample standard deviation:

$\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7$

$s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} } = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702$

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a t confidence interval.

The critical value of t for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262$

*Use a t-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}$

$=176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)$

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0

3 years ago