this is the answer of your question .
<em>Hope</em><em> </em><em>it</em><em> </em><em>helped </em><em>you</em>
C is a mixture!!!!!!!!!!!!!
In 1 mol of CH3OH, you have 4 H-atoms (because 3 H-atoms
are attached to the C-atom, and one H-atom in the OH group). That means
in 0.500 mol of CH3OH, you have 2 H-atoms since it is halved. And then we have Avogadro's constant: 6.02 * 1023.
The question asks for how many hydrogen atoms there are in 0.500 mol CH3OH. Using the numbers that we have (Avogadro's constant and no. of H-atoms), the answer of the question will be something like:
<span>H-atoms in CH3OH = 2 * 6.02 * </span>1023<span> = ~1.2 * 10</span>24
This one is beta decay (the -1 subscript tells us that)
Ggggggggggggggggggggggggggggggggggggggg
