We can first find the number of moles using the ideal gas law equation,
PV = nrT
where P - pressure - 1000 mmHg / 760 mmHg/atm = 1.32 atm
V - volume - 100 x 10⁻³ L
n - number of moles
r - universal gas constant - 0.08206 LatmK⁻¹mol⁻¹
T - temperature in Kelvin - 95 °C + 273 = 368 K
substituting these values
1.32 atm x 100 x 10⁻³ L = n x 0.08206 LatmK⁻¹mol⁻¹ x 368 K
n = 0.00437 mol
molar mass can be determined as follows
molar mass = mass present / number of moles
molar mass = 0.597 g / 0.00437 mol = 136.6 g/mol
molar mass of gas is 137 g/mol
Answer:
The molarity of ethanol is 5.8*10⁻³ M.
Explanation:
Molar concentration is a measure of the concentration of a solute in a solution, be it some molecular, ionic or atomic species.
Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume. It is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units .
Being the molar mass of ethanol 46 , then the number of moles that 40 grams of ethanol contain is calculated by:
So, being:
- number of moles of solute= 0.87 moles
- volume 150 L
Replacing in the definition of molarity:
Solving:
Molarity= 5.8*10⁻³ M
<u><em>The molarity of ethanol is 5.8*10⁻³ M.</em></u>
Answer:
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Al = 1×4 = 4
- Number of atoms in C = 1×3 = 3
- Number of atoms in H = 12×2 = 24
- Number of atoms in O = 12×1 = 12
<em>In product side of equation :-</em>
- Number of atoms in C = 3×1 = 3
- Number of atoms in H = (3×4) + 4(1×3) = 24
- Number of atoms in Al = 4×1 = 4
- Number of atoms in O = 4(1×3) = 12
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
the Molar mass of *235UF6 is 82724.5424 g/mol. i hope this is what you meant and hope it helps