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geniusboy [140]
3 years ago
14

Which scenario involves a

Chemistry
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

Amount of products and reactants is constant...Although,if any of the factors that interfere this scenerio is involved then there will be a shift or change...

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A small cylinder of helium gas used for filling balloons has a volume of 2.20 L and a pressure of 14300 kPa at 25 ∘C. Part A How
Korvikt [17]

Answer:

You can fill 212 balloons.

Explanation:

First we <u>calculate the helium moles in the small cylinder</u>, using <em>PV=nRT:</em>

  • P =  14300 kPa ⇒ 14300 * 0.009869 = 141.13 atm
  • V = 2.20 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

141.13 atm * 2.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • n = 12.70 mol

Then we <u>calculate the number of moles that can fit in a single balloon</u>:

  • 1.22 atm * 1.20 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K
  • n = 0.0599 mol

Finally we <u>divide the total number of available moles by the number of moles in a single balloon</u>:

  • 12.70 mol / 0.0599 mol = 212.09

So the answer is that you can fill 212 balloons.

7 0
2 years ago
A biochemist carefully measures the molarity of magnesium ion in of cell growth medium to be . Unfortunately, a careless graduat
denis23 [38]

Answer:

760 uM

Explanation:

<em>A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97 uM. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 6.0 mL. Calculate the new molarity of magnesium ion in the cell growth medium Be sure your answer has the correct number of significant digits.</em>

The problem here is that the amount of magnesium ion remains the same irrespective of the volume.

Amount of magnesium in the growth medium = <em>molarity x volume</em>

    = 97 x 10^{-6} x 47 x 10^{-3} = 4.559 x 10^{-6}

Then, the volume reduced to 6.0 mL, the new molarity becomes;

<em>molarity = mole/volume </em>

       = 4.559 x 10^{-6}/6 x 10^{-3} = 7.598333 x 10^{-4} M = 759.83333 uM

To the correct number of significant digits = 760 uM

6 0
2 years ago
How many grams of MgCl2 would be needed to make 5.3 liters of a 0.25 molar solution? Round your answer to the nearest 0.01,
GuDViN [60]

Answer: 126.1 grams of are needed to make 5.3 L of 0.25 M solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the mass of solute for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{given mass of solute}}{\text {Molar mass of solute}\times \text{Volume of solution in L}}

0.25M=\frac{x}{95.2g/mol\times 5.3L}

x=126.1g

Thus 126.1 grams of are needed to make 5.3 L of 0.25 M solution

6 0
2 years ago
Calculate the concentration of chloride ions when 100.0 mL of 0.233 M sodium chloride is mixed with 250.0 mL of 0.150 M calcium
serg [7]
The dissociation of both salts NaCl and CaCl₂ are as follows;
NaCl --> Na⁺ + Cl⁻

CaCl₂ --> Ca²⁺ + 2Cl⁻

the molar ratio of NaCl to Cl⁻ is 1:1
therefore number of NaCl moles is equal to number of Cl⁻ ions dissociated from NaCl
then number of Cl⁻ ion moles - 0.233 mol/L x 0.1000 L = 0.0233 mol

molar ratio of CaCl₂ to Cl⁻ ions is 1:2
1 mol of CaCl₂ gives out 2 mol of Cl⁻ ions.
number of CaCl₂ moles - 0.150 mol/L x 0.2500 L  = 0.0375 mol 
then the number of Cl⁻ ion moles - 0.0375 x 2 = 0.0750 

total number of Cl⁻ ion moles = 0.0233 mol + 0.0750 mol = 0.0983 mol
volume of solution - 100.0 + 250.0 = 350.0 mL 

concentration of Cl⁻ = 0.0983 mol / 0.3500 L = 0.281 M
concentration of Cl⁻⁻ is 0.281 M 
4 0
3 years ago
True or False: The only planet that has gravity is the Earth.
taurus [48]

Answer:

False.

Explanation:

all planets have gravity because if they didnt, the gasses and whatever makes up the planet wouldnt be pulled down to the core of the planet, and it would just be floating around in space.

6 0
3 years ago
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