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3 years ago

What is the pressure, in atmospheres, of a 0.108-mol sample of helium gas at a temperature of 20.0°C if its volume is 0.505 L?

Chemistry

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

P = 5.14ATM

Explanation:

Number of moles = 0.108moles

Temperature (T) = 20°C = 20 + 273.15 = 293.15K

Volume V = 0.505L.

Pressure (P) = ?

R = 0.082J/mol.K

From ideal gas equation,

PV = nRT

P = nRT / V

P = (0.108 * 0.082 * 293.15) / 0.505

P = 2.596 / 0.505

P = 5.14ATM

The pressure of the gas is 5.14ATM

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natali 33 [55]

Answer:

63.616

Explanation:

DATA

1. first atomic mass;m1=63

second atomic mass;m2=65
first percentage;p1= 69.2%
second percentage me;p2=30.8%
average mass;avg= ?

SOLUTION

avg= (m1)(p1) + (m2)(p2)

100

avg= (63)(69.2) + (65)(30.8)

100

avg= 4359.6 + 2002

100

avg= 6361.6

100

avg= 63.616

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6 0

3 years ago

A buffer consists of 0.45 M CH3COOH (acetic acid) and 0.35 M CH3COONa. The Ka of acetic acid is 1.8 x 10-5 . a) Calculate the pH

Zigmanuir [339]

Answer:

A) pH of Buffer solution = 4.59

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Explanation:

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$pH = pKa + log\frac{[conjugate base]}{[acid]}$