What is the pressure, in atmospheres, of a 0.108-mol sample of helium gas at a temperature of 20.0°C if its volume is 0.505 L?
1 answer:
Answer:
P = 5.14ATM
Explanation:
Number of moles = 0.108moles
Temperature (T) = 20°C = 20 + 273.15 = 293.15K
Volume V = 0.505L.
Pressure (P) = ?
R = 0.082J/mol.K
From ideal gas equation,
PV = nRT
P = nRT / V
P = (0.108 * 0.082 * 293.15) / 0.505
P = 2.596 / 0.505
P = 5.14ATM
The pressure of the gas is 5.14ATM
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