<u>Answer:</u> The correct option is 
<u>Explanation:</u>
A catalyst is defined as the chemical species that increases the reaction rate but does not participate in it and is left behind after the completion.
A homogeneous catalyst is one that is present in the same phase as the reactants and products.
A heterogeneous catalyst is one that is present in different phase as that of reactants and products.
For the given chemical reaction:
As all the reactants and products are in gaseous state so, the homogeneous catalyst must also be in the gaseous state only.
Hence, the correct option is
Explanation:
a. Average kinetic energy is directly proportional to absolute Kelvin temperature of a gas.
Yes
b. There are no attractive forces and repulsive forces between gas molecules.
Yes
C. Atoms are neither created nor destroyed by ordinary chemical reactions.
No
d. The volume occupied by all of the gas molecules in a container is negligible compared to the volume of the container
Yes
The kinetic molecular theory is one of such theories used to explain the forces between molecules and the energy they posses.
According to the theory;
- The temperature of gas is proportional to the average kinetic energy.
- Molecules are independent of one another and the force of attraction and repulsion between them is negligible.
- volume occupied by gases is negligible compared to the volume of the container.
Law of conservation of matter states that "atoms are neither created nor destroyed by ordinary chemical reactions".
learn more:
Kinetic molecular theory brainly.com/question/12362857
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<h3>Answer:</h3>
89.6 L of O₂
<h3>Solution:</h3>
The balanced chemical equation is as,
CH₄ + 2 O₂ → CO₂ + 2 H₂O
As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,
44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂
So,
88 g CO₂ will be produced by = X L of O₂
Solving for X,
X = (88 g × 44.8 L) ÷ 44 g
X = 89.6 L of O₂
PbSO₄ partially dissociates in water. the balanced equation is;
PbSO₄(s) ⇄ Pb²⁺(aq) + SO₄²⁻(aq)
Initial - -
Change -X +X +X
Equilibrium X X
Ksp = [Pb²⁺(aq)] [SO₄²⁻(aq)]
1.6 x 10⁻⁸ = X * X
1.6 x 10⁻⁸ = X²
X = 1.3 x 10⁻⁴ M
Hence the Pb²⁺ concentration in underground water is 1.3 x 10⁻⁴ M.
[Pb²⁺] = 1.3 x 10⁻⁴ M.
= 1.3 x 10⁻⁴ mol / L x 207 g / mol
= 26.91 ppm
