1 car - 4 wheels
1 motorcycle - 2 wheels
x - number of cars
y - number of motorcycles
so, there are 70 vehicles: x + y = 70
and all togeather they've got 258 wheels: 4*x + 2*y = 258
because each car has 4 wheels, so all car wheels = 4*x,
likewise 2*y for motorcycles
x + y = 70 /* 4
4 x + 2y = 258
4 x + 4 y = 280 (R1)
4 x + 2y = 258 (R2)
2y = 22 /:2 it is R1 - R2
x = 70 - y
y = 11 /motorcycles
x = 70 - 11 = 59 /cars
check:
59 + 11 = 70 ok
59 * 4 + 11 * 2 = 236 + 22 = 258 ok
Answer:
Step-by-step explanation:
a) 3x^2-12x-11=3*x^2-3*2*2*x+3*4-23=3*(x^2-2*2x+2^2)-23=3*(x-2)^2-23
so a= -2 ,b= -23
b) x1=[12+V(12^2-4*3* -11)]/6=12/6+V(144+132)/6=2+2/6V69=2+1/3V69=
2+V69/9=2+V23/3
c=2, d= 23/3
Answer:
Harry has 120$
Step-by-step explanation
6x+5x=220
11x=220
/11 /11
x=20
6 * 20 = 120
I'd apptreciate help w my questions if u can :)
Answer:
y = 3 and y = x + 3
Step-by-step explanation:
The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.
Consider the equation y = x + 3.
Substitute (0, 3).
3 = 0 + 3
So, (0, 3) lies on y = x + 3 and this can also be a part of the system.
Answer:
3x - 6
Step-by-step explanation:
