Answer: c > -25
From the question you can get the equation:
5 - 3c > 80; subtract 5 from both side
-3c > 75; divide -3 from both side
c > -25
So numbers including: -24, -23, -22, -21…
are all numbers that could work
Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² = ![\frac{500}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B500%7D%7B16%7D)
t = ![\sqrt{31.25}](https://tex.z-dn.net/?f=%5Csqrt%7B31.25%7D)
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² = ![\frac{-560}{-16}](https://tex.z-dn.net/?f=%5Cfrac%7B-560%7D%7B-16%7D)
t = ![\sqrt{35}](https://tex.z-dn.net/?f=%5Csqrt%7B35%7D)
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² = ![\frac{1500}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B1500%7D%7B16%7D)
t = ![\sqrt{93.75}](https://tex.z-dn.net/?f=%5Csqrt%7B93.75%7D)
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
Answer:
yes
Step-by-step explanation:
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