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atroni [7]
2 years ago
14

A point Q on a segment with endpoints A (2, −1) and C (4, 2) partitions the segment in a 4:1 ratio. Find Q.

Mathematics
1 answer:
Annette [7]2 years ago
3 0

The point Q on a line segment with end points(2,1) and (4,2) is Q(12/5, -2/5)

<h3>What is a line segment?</h3>

A line segment is a straight line that passes through two given points.

The end points of the line determine how long or short a given line segment would be.

Analysis:

point Q(x, y )

x = \frac{MX1 + NX2}{M+N}

y = \frac{MY1 + MY2}{M+N}

where M :N = 4:1

x1 = 2, x2 = 4, y1 = -1, y2 = 2

x = \frac{4(2) +1(4)}{4+1} = 12/5

y = \frac{4(-1) + 1(2)}{4+1} = -2/5

In conclusion, the point Q is (12/5, -2/5).

Learn more about line segment: brainly.com/question/2437195

#SPJ1

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7 0
3 years ago
Suppose the FAA weighed a random sample of 20 airline passengers during the summer and found their weights to have a sample mean
Orlov [11]

Answer:

Step-by-step explanation:

Given Parameters

Mean, x = 180

total samples, n = 20

Standard dev, \sigma = 30

\alpha = 1 - 0.95 = 0.05 at 95% confidence level

Df = n - 1 = 20 - 1 = 19

Critical Value, t_\alpha, is given by

t_{c}=t_{\alpha, df} = t_{0.05,19} = 1.729

a).

Confidence Interval, \mu, is given by the formula

\mu = x +/- t_c \times \frac{s}{\sqrt{n} }

\mu = 180 +/- 1.729 \times \frac{30}{\sqrt{20} }

\mu = 180 +/-11.5985

191.5985 > \mu > 168.4015

b).

Critical Value, t_{\alpha/2}, is given by

t_{c}=t_{\alpha/2, df} = t_{0.05/2,19} = 2.093

Confidence Interval, \mu, is given by

\mu = x +/- t_c \times \frac{s}{\sqrt{n} }

\mu = 180 +/- 2.093 \times \frac{30}{\sqrt{20} }

    = 180 +/- 14.0403

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8 0
3 years ago
What's the answer to this? Or how do I figure it out?
trapecia [35]
B.) 14/43 
1&2 =7+7
= 14
Bottam:
14 + 8 +6 + 9 +6
= 43
Lastly
= 14/43

6 0
3 years ago
A travel agency books holiday tours to Italy, Greece, and other countries in Europe. A supervisor notes that the probability tha
lutik1710 [3]
P(Greece) =0.28 among tem P(G∩I) = 0.11. We also know tat
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The only data that is missing is te P(Italy)
P(G ∪ I ) = P(G) + P(I) - P(G∩ I)
1 =0.28 + P(I) so P(I) = 0.72
P(G) = 0.28 (including the 0 .11)
P(I) = 0.72 (including the  0.11)
P(G and I) =0.11
3 0
4 years ago
Read 2 more answers
In the input/output rule: y = -3x - 7 What
tensa zangetsu [6.8K]

Answer:

-22

Step-by-step explanation:

Plug in 5 for x.

y = -3(5) - 7

y = -15 - 7

y = -22

4 0
3 years ago
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