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Thepotemich [5.8K]
3 years ago
8

Given the system of equations, what is the solution? 5x - 4y = 7 x = 5 - 3/2 y

Mathematics
2 answers:
xenn [34]3 years ago
8 0
The answer is A


You can solve this by equation the two equations, by substitution method or elimination. Let's choose the substitution since Equation 2 has already X isolated
-take the X in equation 2 and substitute in the first equation
So, You should have 5 (5-3/2 y) -4y =7
Get y ( I'll assume you know how to simplify and find y by yourself )
y=36/23
-Now take y and substitute it in the first equation or the second equation (it doesn't really matter)
Substituting y in Equation 2:
x=5- 3/2 (36/23)
=> x= 61/23

So answer is A where (x,y) is (61/23, 36/23)
tester [92]3 years ago
8 0

Answer:

Option A is correct.

Step-by-step explanation:

Given system of equations are

5x - 4y = 7 ...............(1)

x = 5 - 3/2y .................(2)

value of x from equation (2), put in equation (1)

5(5-\frac{3}{2}y)-4y=7

25-\frac{15}{2}y-4y=7

-\frac{15}{2}y-\frac{8}{2}y=7-25

\frac{-15-8}{2}y=-18

\frac{-23}{2}y=-18

y=-18\times\frac{-2}{23}

y=\frac{36}{23}

Now, Value of x = 5-\frac{3}{2}\times\frac{36}{23}=5-\frac{54}{23}=\frac{115-54}{23}=\frac{61}{23}

Solution of given system is (\frac{61}{23},\frac{36}{23})

Therefore, Option A is correct.

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Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

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Using Table

P(0 ≤ Z ≤ 1) = 0.3413

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2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

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Using Table

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