Answer:
-¹²/₅
Step-by-step explanation:
Let cos a = -⁵/₁₃
Then tan a = sin a/cos a
= [√(1 - cos²a)]/cos a
= {√[1 - (-⁵/₁₃)²]}/(-⁵/₁₃)
= -[√(1 - ²⁵/₁₆₉)] × ¹³/₅
= -[(√(¹⁴⁴/₁₆₉ )] × ¹³/₅
= -¹²/₁₃ × ¹³/₅
= -¹²/₅
tan(arccos (-⁵/₁₃)) = -¹²/₅
The diagram shows the 2nd quadrant of a circle with radius 13, cos a = -⁵/₁₃, and tan a = ¹²/₍₋₅₎ = -¹²/₅.
The question is saying a number is square, then squared again, and finally square again, making that number squared itself up to 3 times. So we take 6561 and we square root it 3 times. Square root of 6561 is 81, square of 81 is 9, and finally square root if 9 is 3. The final answer is 3.
Answer:
2nd one
Step-by-step explanation:
when it's a 45 45 and 90 triangle, it's 1, 1, sqrt 2, but now since the 1 is sqrt 2, v is sqrt 2, and u and sqrt 2 times sqrt 2, which is 2
Step-by-step explanation:
To find coordinates, we need the equation of the line segment with restrictions. I think you meant to say “line segment” as lines go infinitely in 2 directions and could not be broken up into ratios. Let’s say your segment is 24 feet long. You could then label AB as 5x and BC as x since that is a ratio of 5:1 …………We’d then have an equation
5x + x = 24 … or 6x = 24…..or x = 4 which would make AB = 20 and BC = 4…but this would not give us coordinates of points.
