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MrRissso [65]
3 years ago
14

HELP HELP HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Arrange the functions in ascending order, starting with the function t

hat eventually has the least value and ending with the function that eventually has the greatest value.
5x + 3
8x + 3
x^2 + 4
5x
7x
x2
Mathematics
1 answer:
san4es73 [151]3 years ago
6 0
If x is squared, that will be biggest by the end because it gets bigger the quickest. x^2 + 4 is always 4 greater than x^2, no matter what the value of x is.

5x+3 is always 3 greater than 5x also.

Besides that, you can rank them based on their slopes (5x < 7x < 8x, etc.)

So,
5x
5x + 3
7x
8x + 3
x^2
x^2 + 4

You can also just say “eventually” means that they’re asking to find the values of each when x is really big. so just choose x=100, and plug that into each one.

So, to check that order:
5(100) = 500
5(100) + 3 = 503
7(100) = 700
8(100) + 3 = 803
(100)^2 = 10,000
(100)^2 + 4 = 10,004

Those are in ascending order, so that must be the right order!
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Which is true about the completely simplified difference of the polynomials 6x6 − x3y4 − 5xy5 and 4x5y + 2x3y4 + 5xy5?
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An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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6h: 11a+4b-5

hope this helps and is correct!!
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