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SCORPION-xisa [38]
3 years ago
15

How did corana virus start​

Chemistry
2 answers:
Veseljchak [2.6K]3 years ago
7 0

Answer:

we know that it originally came from an animal, likely a bat. At this time, there is no evidence that animals play a significant role in spreading the virus that causesd

Explanation:

Amiraneli [1.4K]3 years ago
6 0

Answer:

THE VIRUS DIDNT COME FROM NO BAT!

Explanation:

THE VIRUS STARTED IN CHINA IN A LAB AND CHINA DIDNT EVEN TELL THE USA ABOUT IT THEY HIT IT FROM US. WHEN CHINESE PEOPLE WERE TRAVELING TO THE USA IT SPREADED.

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Why does buck ministerfullerene act as a good lubricant
MakcuM [25]

Answer:

Its molecules are made up of 60 carbon atoms joined together by strong covalent bonds. Molecules of C 60 are spherical. There are weak intermolecular forces between molecules of buckminsterfullerene. These need little energy to overcome, so buckminsterfullerene is slippery and has a low melting point.

Explanation:

5 0
3 years ago
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3. Calculate the answers to the appropriate number of significant figures. e) 43.678 x 64.1 = f) 1.678/0.42 =
Sophie [7]
Where’s the pictures
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Which is not a compound?Electrons spin in shells around the nucleus. The closest shell (n = 1) can contain a maximum of _____ el
melisa1 [442]

The closest shell (n = 1) can contain a maximum of 2 electrons.

6 0
4 years ago
Why don't some people want a relationship with God?
mr_godi [17]
Some fear that they won't be able to have fun anymore if they accept God, some are afraid of what others might think of them if they accept God, some think they are too messed up to have a relationship with God, and the list goes on and on. Who knows why someone would refuse.
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6 0
3 years ago
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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
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