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3 years ago

How many moles of argon are in 30.6L at 28K and 658 mmHg?

Chemistry

1 answer:

lesantik [10]3 years ago

6 0

Answer : The number of moles of argon gas is, 11.5 mol

Explanation :

To calculate the moles of argon we are using ideal gas equation as:

$PV=nRT$

where,

P = pressure of argon gas = 658 mmHg = 0.866 atm (1 atm = 760 mmHg)

V = volume of argon gas = 30.6 L

n = number of moles of argon gas = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of argon gas = 28 K

Now put all the given values in the above formula, we get:

$(0.866atm)\times (30.6L)=n\times (0.0821 L.atm/mol.K)\times (28K)$

$n=11.5mol$

Therefore, the number of moles of argon gas is, 11.5 mol

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