We know that
mGJI+117.33°=360° (full circle)
so
mGJI=360°-117.33°-----> 242.67°
the answer is
242.67°
Answer:
x = -2
Step-by-step explanation:
2(x-2) = 3(x+2)-8
Multiply the 2 and 3 out to the numbers in the parentheses. Don't multiply the 3 out to the -8 because it is outside of the parentheses.
2x-4 = 3x+6-8
Combine the 6 and -8
2x-4 = 3x-2
Subtract 2x from both sides
-4 = x-2
Add 2 to both sides
-2=x
Jim will probably need 6 cups of strawberries to yeild 10 jars
Step-by-step explanation:
V=pi r^2h
V=3.14x3^2x7
=197.82
Answer:
Step-by-step explanation:
First, the acceleration of gravity is -9.8m/s^2. This still works out since the formula uses 1/2 of it.
Hopefully you see where the other parts come from. Anyway, standard form of a quadratic is ax^2+bx+c=0. So this is almost there. You just need to subtract that 2.1 from both sides.
-4.9t^2+7.5t+-.3=0
Now with this, since it has taken into account the height that the ball was caught with that 2.1, you just need to find the 0s, which is what the quadratic equation does.
The quadratic equation is (-b±sqrt(b^2-4ac))/(2a) and we have a = -4.9, b = 7.5 and c = -.3. Remember you want to keep the signs. Now we just plug in.
(-b±sqrt(b^2-4ac))/(2a)
(-7.5±sqrt((-7.5)^2-4*-4.9*-.3))/(2*-4.9)
(-7.5±sqrt(56.25-5.88))/(.9.8)
(-7.5±sqrt(50.37))/(-9.8)
(-7.5±7.097)/(-9.8)
The plus or minus means there are two equations.
(-7.5+7.097)/(-9.8) and (-7.5-7.097)/(-9.8) So we will solve for both of these.
.04112 and 1.4895. That means these two times are when the ball is at 2.1 meters. One time on the way up and one time on the way down. We can safely assume that the other player catches the ball on the way down, so we want to use the second time, so 1.4895 seconds.
