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goldenfox [79]
3 years ago
11

How to describe a transformation?

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
The horizontal shift depends on the value of h . The horizontal shift is described as: g(x)=f(x+h) g ( x ) = f ( x + h ) - The graph is shifted to the left h units. g(x)=f(x−h) g ( x ) = f ( x - h ) - The graph is shifted to the right h units.
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Show your work (40 points) ASAP
Alik [6]

Answer:

x=8

The value of z is 49°.

4 0
4 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️PLEASE HELP!!! PLEASE EXPLAIN AND ONLY ANSWER IF YOU KNOW YOU HAVE THE CORRECT ANSWE
Lena [83]

We are given the expression x³ - 2y² - 3x³ + z⁴. We have to evaluate it at a given set of x, y, and z values. Before then, let's combine like terms.

x³ - 2y² - 3x³ + z⁴

= -2x³ - 2y² + z⁴ <-- by combining like terms

Now we evaluate for x=3 y=5 z = -3

= -2(3³) - 2(5²) + (-3⁴) <-- by putting in for x, y, z

= -2(27) - 2(25) + 81 <--- parentheses and exponents first in order of operations

= -54 - 50 + 81 <---- multiplication is next

= -4 + 81

= 77


Thus, we evaluate and it's 77.

7 0
4 years ago
Can u heeeelp pleeease
navik [9.2K]

Answer:

t ≤ 12

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A job fair was held at the Student Union. 25% of the students who attended received job offers. Of all of the students at the jo
vovangra [49]

Answer:

A) Both events are not independent.

B) Both events are not mutually exclusive

C) 8.33%

D) 80%

Step-by-step explanation:

A) Both events are not independent. This is because, If B occurs it means that it is very likely that J will occur as well.

B) Both events are not mutually exclusive. This is because it is possible for both events J and B to occur at the same time.

C) we want to find the probability that Joe who is not a business student will receive the job offer.

This is;

P(J|Not B) = P(J & Not B)/P(Not B)

Now,

P(J & Not B) = P(J) – (P(B) × P(J | B))

25% of the students who attended received job offers. Thus; P(J) = 0.25

40% were from the College of Business. Thus;

P(B) = 0.4

Among the business students, 50% received job offers. Thus;

P(J|B) = 0.5

Thus;

P(J & Not B) = 0.25 - (0.4 × 0.5)

P(J & Not B) = 0.25 - 0.2

P(J & Not B) = 0.05

Since P(B) = 0.4

Then, P(Not B) = 1 - 0.4 = 0.6

Thus;

P(J|Not B) = 0.05/0.6

P(J|Not B) = 0.0833 = 8.33%

D) This probability is represented by;

P(B | J) = P(B & J)/P(J)

P(B & J) = (P(B) × P(J | B)) = (0.4 × 0.5) = 0.2

P(B | J) = 0.2/0.25

P(B | J) = 0.8 = 80%

5 0
3 years ago
Factor the GCF: 12a^3b + 8a^2b^2 — 20 ab^3
geniusboy [140]

Answer:

GCF is 4ab

And the expression will be: 4ab ( 3a^2+2ab-5b^2)

Step-by-step explanation:

Factor the GCF :

12a^3b + 8a^2b^2-20 ab^3

We need to find the common terms that are common in each of the term given above

12,8 and 2 are all divisible by 4

a is common in all terms and b is also common in all terms,

So, GCF is 4ab

Taking 4ab common

12a^3b + 8a^2b^2-20 ab^3=4ab ( 3a^2+2ab-5b^2)

5 0
3 years ago
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