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Kobotan [32]
3 years ago
5

Cameron bought a used car for $4,500. He made a down payment of $1,200 and agreed to pay the remaining balance in monthly paymen

ts of $300 each.
Which equation can be used to find m, the number of months it will take Cameron to pay off his car? (7.10A)


F 4,500 = 1,200 + 300m
F 4,500 = 1,200 + 300m

G 4,500 = –300 + 1,200m
G 4,500 = –300 + 1,200m

H 4,500 = 300 + 1,200m
H 4,500 = 300 + 1,200m

J 4,500 = 1,200 – 300m
J 4,500 = 1,200 – 300m
Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

4500 = 1200 + 300m

Step-by-step explanation:

Given

Total = 4500

Base\ Amount = 1200

Payment = 300 monthly

Required

Write an expression to determine the number of months

The total can be expressed using:

Total = Base\ Amount +Payment * Number\ of\ months

Substitute value for each term

4500 = 1200 + 300 * m

4500 = 1200 + 300m

Hence:

Option F answers the question

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On a certain hot​ summer's day, 643 people used the public swimming pool. The daily prices are $1.50 for children and $2.00 for
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Step-by-step explanation:

Number of people swam at pool = 643

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Let,

x be the number of children

y be the number of adults

According to given statement;

x+y=643    Eqn 1

1.50x+2.00y = 1161.50   Eqn 2

Multiplying Eqn 1 by 2

2(x+y=643)\\2x+2y=1286\ \ \ Eqn\ 3\\

Subtracting Eqn 2 from Eqn 3

(2x+2y)-(1.50x+2.00y)=1286-1161.50\\2x+2y-1.50x-2.00y=124.50\\0.5x=124.50

Dividing both sides by 0.5

\frac{0.5x}{0.5}=\frac{124.50}{0.5}\\x=249

Putting x=249 in Eqn 1

249+y=643\\y=643-249\\y=394

249 children and 394 adults swam at the public pool.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/5798698
  • brainly.com/question/5758530

#LearnwithBrainly

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Follows are the solution to this question:

Step-by-step explanation:

Given:

s_1 = 21 \ \  t_1 = 1\\\\s_2 = 59 \ \ t_2 = 2\\\\s_3 = 141 \ \  t_3 = 4

All points are on the graph including its quadratic function, in order to install their coordinates to values of x and y with the following values:

y= ax^2 + bx + c\\\\21=a+b+c      Inserting the coordinates of the first point

y= ax^2 + bx + c\\\\59 =4a+2b+c              Inserting the coordinates of the second point

y= ax^2 + bx + c\\\\141=16a+4b+c       Inserting the coordinates of the third point

5 0
3 years ago
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