Question

Please help me with Algebra 2 questions (2).

Answer 1

8. The simplified form of the expression is $- 5 x^{\frac{4}{5}}y^{3}$

11. The value of x is 4

Simplifying an expression

From the question, we are to simplify the give expression

The given expression is

$y^{3}\sqrt[5]{32x^{4} } - 7\sqrt[5]{x^{4}y^{15} }$

$y^{3} (32x^{4} )^{\frac{1}{5} } - 7(x^{4}y^{15} )^{\frac{1}{5}$

$y^{3} \times 32^{\frac{1}{5} } x^{\frac{4}{5} } - 7 \times x^{\frac{4}{5}}y^{\frac{15}{5}}$

$y^{3} \times 2^{5 \times} ^{\frac{1}{5} } \times x^{\frac{4}{5} } - 7 \times x^{\frac{4}{5}}y^{3}$

$y^{3} \times 2 \times x^{\frac{4}{5} } - 7 \times x^{\frac{4}{5}}y^{3}$

$2 x^{\frac{4}{5} } y^{3} - 7 x^{\frac{4}{5}}y^{3}$

$= - 5 x^{\frac{4}{5}}y^{3}$

11. $\frac{1}{2}(5x+7 )^{\frac{2}{3} } =\frac{9}{2}$

Multiply both sides by 2

$2 \times \frac{1}{2}(5x+7 )^{\frac{2}{3} } =2 \times \frac{9}{2}$

$(5x+7 )^{\frac{2}{3} } =9$

Multiply both sides by a power of 3/2

$(5x+7 )^{\frac{2}{3} \times {\frac{3}{2} } } =9^{\frac{3}{2} }$

$(5x+7 )=3^{2 \times} ^{\frac{3}{2} }$

$5x+7 =3^{3}$

$5x+7 =27$

$5x =27-7$

$5x = 20$

$x = \frac{20}{5}$

x = 4

Hence,

8. The simplified form of the expression is $- 5 x^{\frac{4}{5}}y^{3}$

11. The value of x is 4

Learn more on Simplifying expressions here: brainly.com/question/11688560

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