If there was an inverse relationship between the temperature and the volume, our daily lives change because in high temperature things will contract.
<h3>What if there was an inverse relationship between the temperature and the volume?</h3>
If there was an inverse relationship between the temperature and the volume then with increasing temperature decrease occur in the volume of a substance. If this type of relationship is present in the world, the objects will contract when the temperature is high and expand when the temperature is low which make the solid materials expand at winter and contract at summer season.
So we can conclude that if there was an inverse relationship between the temperature and the volume, our daily lives change because in high temperature things will contract.
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Answer:
The electronegativity of fluorine compare to the electronegativity of oxygen and chlorine as below
Explanation:
Fluorine has the highest electronegativity than oxygen, and chlorine.
Explanation
Generally the electronegativity increase across the period ( from the left to the right) and decreases down the group.
Both oxygen and fluorine are in period 2 in periodic table. since fluorine is on fur right side as compared to oxygen , fluorine has higher electronegativity than oxygen.
On the other side Fluorine and chlorine are in the same group in periodic table. fluorine is at the top of the group while chlorine is at the bottom therefore fluorine has higher electronegativity than chlorine.
Covalent bonds keep the hydrogen and oxygen atoms together
Answer: I don’t really know
Explanation:
I don’t know sorry
Answer:
freezing point (°C) of the solution = - 3.34° C
Explanation:
From the given information:
The freezing point (°C) of a solution can be prepared by using the formula:
where;
i = vant Hoff factor
the vant Hoff factor is the totality of the number of ions in the solution
Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3
= 1.86 °C/m
m = molality of the solution and it can be determined by using the formula
which can now be re-written as :
molality = 0.599 m
∴
The freezing point (°C) of a solution can be prepared by using the formula:
the freezing point of water - freezing point of the solution
3.34° C = 0° C - freezing point of the solution
freezing point (°C) of the solution = 0° C - 3.34° C
freezing point (°C) of the solution = - 3.34° C
