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Studentka2010 [4]
3 years ago
14

How many mL of a 0.250M sodium hydroxide solution is needed to neutralize 25.0 mL of a 0.430M sulfuric acid solution?

Chemistry
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

86.0 mL

Explanation:

i just did the USA test prep

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The formula for mole fraction is:

mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

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Converting mmol to mol:

1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol

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For moles of water:

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Density = \frac{mass}{volume}

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