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Maslowich
2 years ago
15

For a population with μ = 60 , z-score =3.15, and σ = 10. Find random variable / data value X . Round your answer to the nearest

hundredths place. Round your answer to 2 decimal places.
Mathematics
1 answer:
Artyom0805 [142]2 years ago
7 0

Answer:

  X = 91.50

Step-by-step explanation:

The relation that defines a Z value can be used to find an X value when the appropriate parameters are given.

<h3>Z-score</h3>

The equation for finding the Z-score associated with an X-value is ...

  Z = (X -μ)/σ

Solving this for X using the values given, we have ...

  3.15 = (X -60)/10

  31.5 = X -60 . . . . . . . multiply by 10

  91.5 = X . . . . . . . . add 60

The random variable value is ...

  X = 91.50

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Factor completely.<br>28 - 7x^2 ​
FrozenT [24]

Answer:

7(4 - x^2)

Step-by-step explanation:

Well you just factor out 7, since that is the GCF. 7(4 - x^2)

Hope this helps

8 0
2 years ago
4x-2=3x+4 solve this
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

x=6

8 0
3 years ago
Read 2 more answers
Can anyone help me please
Andrew [12]

I think the answer is #4

4 0
2 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

3 0
3 years ago
Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.
kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

\frac{4}{8}=\frac{1}{2}

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent

8 0
10 months ago
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