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Flauer [41]
2 years ago
13

Cos 0 = . Find tan 0.

Mathematics
1 answer:
WITCHER [35]2 years ago
7 0

Answer:

b

Step-by-step explanation:

15/8

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When constructing parallel and perpendicular lines, how are the steps similar?
Schach [20]
Similar steps:

1. You need to draw a reference line first( It's trivial but hey, it's similar)

2. You need to draw the other line with pre-defined slope( parallel with same slope, perpendicular with the product of the slope to be -1)
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Express the given quantity as a single logarithm and simplify: 3logx+2log(y-2)-5logx
storchak [24]
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>. 
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Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>. 
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span> 
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Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span> 
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span> 
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Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method. 
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span> 
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Simplify each term<span>. 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span> 

</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span> 
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span> 
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Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)

</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span> 
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Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>. 
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Replace into larger expression<span>. 
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3 0
3 years ago
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Answer: Have a good day. I’m sorry you have to go through this, my head already hurts and I am just lōoking at it.

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Find the indicated sum of each sequence S8 of -2,-13,-24,-35
valentina_108 [34]

Answer:

The sum of the arithmetic sequence is S_{8}=-324.

Step-by-step explanation:

A sequence is a set of numbers that are in order.

In an arithmetic sequence the difference between one term and the next is a constant.  In other words, we just add the same value each time infinitely.

If the first term of an arithmetic sequence is a_1 and the common difference is d, then the nth term of the sequence is given by:

                                                  a_{n}=a_{1}+(n-1)d

For the sequence

                                                -2,-13,-24,-35,...

The pattern is continued by adding -11 to the last number each time.

An arithmetic series is the sum of an arithmetic sequence.  We find the sum by adding the first, a_1 and last term, a_n, divide by 2 in order to get the mean of the two values and then multiply by the number of values, <em>n</em>

<em>                                                     </em>S_{n}=\frac{n}{2}(a_{1}+a_{n})<em />

The sum of the arithmetic sequence is

a_{8}=-2+(8-1)(-11)=-2-77=-79

S_{8}=\frac{8}{2}(-2-79})=4\left(-2-79\right)=4\left(-81\right)=-324

3 0
3 years ago
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ziro4ka [17]

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Step-by-step explanation:

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