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hammer [34]
2 years ago
10

According to the Laws of Proportionality, if a resistor in a parallel circuit has twice the resistance of a second resistor, it

will have _______________ the current of the second resistor.
Physics
1 answer:
sineoko [7]2 years ago
7 0

Answer:

When a resistor in a parallel circuit has twice the resistance of a second resistor, then the resistor has half the current of the second resistor.

Explanation:

It is given that the parallel circuit has two resistors. One is twice the second resistor. It is required to find the current in the first resistor in terms of the second resistor.

Let us consider R and S are in parallel and the potential difference is V on each of the resistors.

If the source current is I, then, the current through the resistor R is,

I_R=\frac{S}{R+S}\times I

And similarly, the current through the resistor S is,

I_S=\frac{R}{R+S}\times I

Therefore, the ratio of the currents is,

$$\begin{aligned}\frac{I_R}{I_S}&=\frac{\frac{S}{R+S}\times I}{\frac{R}{R+S}\times I}\\&=\frac{S}{R}\end{aligned}$$

Here, let, the second resistor is, S=r, then the first resistor, R=2r.

Therefore,

$$\begin{aligned}\frac{I_R}{I_S}&=\frac{r}{2r}\\\rightarrow I_R&=\frac{1}{2} I_S\end{aligned}$$

To know more about the current division in a parallel circuit, refer to:

brainly.com/question/9764589

#SPJ4

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sdas [7]

Answer:0.8\ mm

Explanation:

Given

length of wire l=75\ cm

change in length \Delta l=1.85\ mm

mass of wire m=10\ kg

Young's modulus for silver E=7.9\times 10^{10}\ N/m^2

load on wire F=mg

F=10\times 9.8=98\ kg

change in length is given by

\Delta l=\dfrac{Pl}{AE}

Where A=area of cross-section

A=\dfrac{Pl}{\Delta lE}

A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}

A=\dfrac{73.5}{14.615\times 10^{7}}

A=5.029\times 10^{-7}\ m^2

also wire is the shape of cylinder so cross-section is given by

A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2

\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }

\Rightarrow d^2=64.02\times 10^{-8}

\Rightarrow d=8\times 10^{-4}\ m

\Rightarrow d=0.8\ mm

4 0
3 years ago
Two masses are connected by a string which passes over a pulley with negligible mass and friction. One mass hangs vertically and
monitta

Answer:

a=2,5m/s^2

Explanation:

From the question we are told that:

Coefficient of kinetic friction \mu= 0.200

Vertical Mass M_v=3kg

Horizontal mass M_h=3.00kg  

Generally the equation for kinetic force F_k is mathematically given by

F_k=\mu N\\F_k=0.2*3\\F_k=0.6

Generally the equation for T is mathematically given by

For M_v=3kg3g-T=3a

For M_h=3kg

T=M_v V+F_k\\T=3.0a+0.6

Therefore substituting

3-3a-0.6=3a\\2.4g=6a

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3 years ago
True or False: Our food has potential energy?
DanielleElmas [232]

Hello User,

Answer is yes.

Explanation

<em>At the most fundamental level, chemical energy is stored in food as molecular bonds. These molecular bonds represent potential energy, which is either very stable, such as in fat molecules, or very active and transitory, such as in ATP molecules.</em>

Hope it helps you... pls mark brainliest

3 0
3 years ago
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Two point charges lie on the x axis. A charge of + 2.20 pC is at the origin, and a charge of − 4.80 pC is at x=−11.0cm. What thi
k0ka [10]
As we know that electric field at any point caused due to a point charge given by, kQ/r^2

Where, k is dielectric constant of medium, Q is the point charge and r is the distance between the point charge and point where electric field is to be measured.

Let us assume a charge of q is placed at x=+20cm to make electric field at
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Total electric field at x=+10cm can be shown by equation,

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q)/(10-20)^2  = 0

=> 2.20 X 10^-14 - 1.09 X 10^-14 + q X 10^-2 = 0

=> q = 1.09 X 10^-12 - 2.20 X 10^-12

=> q = -1.1 X 10^-12 Coulombs or -1.1 pC
4 0
4 years ago
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