Answer:
The coefficient of static friction between the coin and the turntable is 0.51
Explanation:
at the time of the slip:
centripetal force = frictional force
mv^2/r = x*m*980
v^2/r = 980x
x = v^2/980r
= [(120)^2]/[980*29]
= 0.51
Therefore, The coefficient of static friction between the coin and the turntable is 0.51
It’s GAT because I just learned about this
Answer:
4N
Explanation:
a = (7-3)/5 = 0.8m/s^2
F = ma = (5)(0.8) = 4 Newtons
Ways to increase friction
- increase the area of contact
- increase the roughness of the contact materials
- dry up or take away any lubricant
- increase the pressure on the contact
