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zavuch27 [327]
3 years ago
14

Challenge

Physics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

Explanation:

500 W = 500 J/s

500 J/s(2 min(60 s/min) = 60000 J

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Thorium^+2
Bad White [126]

Answer:

chemical symbol: Th

atomic number:90

protrons :90

neutrons:142

group#:4

period#: 9

Explanation:

you take the atomic weight (232.038)and subtract the atomic number to get (90) which is your neutrons

6 0
3 years ago
Which one please hurry . And please be right ..
Elis [28]

Answer:

IN MOTION

Explanation:

An apparent change in the frequency of waves, as of sound or light, occurring when the source and observer are in motion relative to each other, with the frequency increasing when the source and observer approach each other and decreasing when they move apart.

8 0
3 years ago
Read 2 more answers
A vehicle travels from a 30m marker to a 100m marker. What is the change in distance
alexgriva [62]

70 meters is your answer

Note that the beginning is the 30 meter mark, and the ending is the 100 meter mark. Subtract the beginning amount from the end:

100 - 30 = 70

The vehicle traveled 70 meters.

~

8 0
3 years ago
The odometer of a car reads 57321 km when the clock shows the time 8.30 am. What is the distance moved by the car, if at 8.50 am
malfutka [58]

Answer:

0.75km/min

Explanation:

I haven't learnt physics at all but I'll try

57336 - 57321 = 15km (Difference)

8.50 am - 8.30 am = 20 minutes (Difference)

If the car odometer adds up 15km every 20 minutes...

20 mins = 15km

1 min = 15 ÷ 20 = 0.75km

3 0
3 years ago
A cylinder with initial volume V contains a sample of gas at pressure p. On one end of the cylinder, a piston is let free to mov
Elina [12.6K]

Answer:

The work done on the gas = 2PV

Explanation:

In this question, we need to apply the basic gas laws to determine the word done.

For this question, we need to draw a PV diagram (a pressure-volume diagram), which I have made and attached in the attachment. So please refer to that attachment. I will be using this diagram to solve for the work done on the gas.

So, Please refer to the attachment number 1. where x -axis is of volume and y-axis is of pressure.

As we know that, the work done on the gas is equal to the area under the curve.

W = Area of the triangle

W = 0.5 x ( base) x ( height)

W = 0.5 x (BC) x (AC)

W = 0.5 x (3V-V) x (3P-P)

W = 2PV

Hence, the work done on the gas = 2PV

4 0
3 years ago
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