Metal things that pull together
The coefficient of kinetic friction between the block and the incline is 0.168.
<h3>
Coefficient of kinetic friction</h3>
The coefficient of kinetic friction is determined from the principle of conservation of energy as follows;
distance traveled on the incline = L
L = h/sin35
L = 1.743 h
Since it takes twice the time travel down,
velocity to slide = 1.743 h/2t = 0.871 v
- v is the velocity to drop from the vertical height
K.E of the block when it slides = ¹/₂mv₁² = ¹/₂m(0.871v)² = 0.871²(K.E to fall) = 0.758K.E to fall straight down
<h3>Energy lost to friction</h3>
1 - 0.758 = 0.24
<h3>Conservation of energy</h3>
μmgcos(35) = 0.24(mgsin(35)
μcos(35) = 0.24(sin(35)
μ = 0.168
Learn more about coefficient of kinetic friction here: brainly.com/question/20241845
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Required Heat = Q
Q = Mass * specific heat of water * change in temp.
Q = 5g * 1g/cal*degC * 20degC
Q = 100 cal of heat is required
To convert calories to Joules,
1 cal = 4.184 Joules
100cal = 418.4 J of heat is needed
Answer:
= 0.7 A, = 1.3 A and ε = 7.4 V
Explanation:
From the given circuit, applying Kirchhoff's rule;
Ammeter reading, = 2 A
⇒ = + = 2 A
Dividing the circuit to loops 1 and 2.
a. From loop 1,
15 + 7 - 5 = 0
15 + 7 - 10 = 0 (since = 2 A)
7 - 5 = 0
= 0.7 A
But, = +
⇒ 2 = 0.7 +
= 1.3 A
b. From loop 2,
ε + 2 - 5 = 0
ε + 2 - 10 = 0
ε + 2.6 - 10 = 0
ε - 7.4 = 0
ε = 7.4 V
Therefore, = 0.7 A, = 1.3 A and ε = 7.4 V.
Explanation:
Density is mass divided by volume:
D = M / V
Given V = 79000 cm³ and D = 13.6 g/cm³:
13.6 g/cm³ = M / (79000 cm³)
M = 1,074,400 g
M = 1,074 kg
Round as needed.