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pentagon [3]
2 years ago
7

Please help! I will give you lots of points!!!

Mathematics
1 answer:
zheka24 [161]2 years ago
3 0

A <em>bisector</em> is a line that divides either a given line or an angle into <u>two</u> equal parts. The <em>answer </em>to the given question is in the <u>attachments</u> to this answer.

The process of <u>bisection</u> implies dividing a given angle or line into<em> two</em> equal parts. Thus a bisector should be constructed.

The <u>construction</u> required is as given below:

For figure 1:

  • With <em>center</em> S and any radius, draw an arc to<u> intersect</u> S and T.
  • Using the <u>end</u> of the arc on SR and a greater radius, draw two arcs.
  • Using the <em>end</em> of the arc on ST and the same radius, draw another arc to <em>intersect</em> the previous arc.
  • Join S to the point of <em>intersection</em> of the arcs by a straight line. Thus this line is the required <u>bisector</u> of <RST.

For figure 2:

  • With <em>center</em> u and any radius, draw an arc to <u>intersect</u> T and V.
  • Using the end of the arc on uT and a greater radius, draw two arcs.
  • Using the end of the arc on uV and the same radius, draw another arc to intersect the previous arc.
  • Join u to the point of<u> intersection </u>of the arcs by a straight line. Thus this line is the required<em> bisector</em> of <TuV.

For figure 3:

  • With center B and any radius, draw an arc to <em>intersect</em> A and C.
  • Using the end of the arc on AB and a greater radius, draw two arcs.
  • Using the end of the arc on BC and the same radius, draw another arc to<u> intersect</u> the previous arc.
  • Join B to the point of<em> intersection</em> of the arcs by a straight line. Thus this line is the required<u> bisector</u> of <ABC.

The required construction is as shown in the <u>attachments</u> to this answer.

For more clarifications on bisection of angles, visit: brainly.com/question/12028523

#SPJ1

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Answer:

Part A) x=9 and m∠FGH=29°

Part B) m∠HGI=29°

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Step-by-step explanation:

Part A) Solve for x and find m∠FGH

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Part B) Find the measure of angle HGI

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Remember that

m∠FGH=m∠HGI

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m∠HGI=5(9)-16=29° -----> is correct

Part C) Find the measure of angle FGI

m∠FGI=m∠FGH+m∠HGI

substitute the values

m∠FGI=29°+29°=58°

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