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uranmaximum [27]
2 years ago
14

Consider the functions f(x) = -2(x-3)² + 2 which is represented by the graph

Mathematics
1 answer:
ehidna [41]2 years ago
6 0

The intervals of the function on the graph are:

  • Domain = (-∝, ∝)
  • Range = (-∝, 2]
  • Increases (-∝, 3]
  • Decreases [3, ∝)

<h3>The key features of the function?</h3>

The function is given as:

f(x) = -2(x-3)² + 2

See attachment for the graph.

From the graph, we have;

Domain = (-∝, ∝)

Because it takes all real values as its input

Range = (-∝, 2]

Because it has a vertex of (3, 2) and the vertex is a maximum

Also, it increases on the interval (-∝, 3] and decreases on the interval [3, ∝)

Read more about function interval at:

brainly.com/question/27831985

#SPJ1

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Answer: 12

Explanation:

add 17 to both sides

x = -5 + 17 = 12

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Find the square root of 156.25 by division method
vampirchik [111]
Hello,

I don't know the divison method but is it these one?

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What is the LCD of , 3/4 ,4/5 and 7/10
lesantik [10]

Answer:

20

Step-by-step explanation:

20 is divisible by 4, 5 and 10

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The blades of a windmill turn on an axis that is 40 feet from the ground. The blades are 15 feet long and complete 3 rotations e
astraxan [27]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

a = 15\ ft

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

k = 40\ ft

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = 2\pi

1 minute = 60 sec.

So:

w = \frac{3(2\pi)}{60}\ rad/s

w = \frac{\pi}{10}\ rad/s

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

3 0
4 years ago
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Q18. The sum of the first N terms of an arithmetic series, S, is 292 The 2nd term of S is 8.5 The 5th term of Sis 13 Find the va
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Step-by-step explanation:

Sn= a+[n-1]d

S2= a+[2-1]d

8.5 = a+d _______Equation 1

S5 = a+[5-1]d

13=a+4d ________Equation 2

Subtract Equation 1 from Equation 2

13=a+4d

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8.5= a+d

________

4.5= 3d

d=1.5

Substituting d=1.5 in equation 1

8.5=a+1.5

a=8.5-1.5

a=7

Sum of terms of an A.P =

Sn= n/2[2a+(n-1)d]

292= n/2[2×7+(n-1)d]

292=n/2[14+(n-1)1.5

292×2=n[14+(n-1)1.5]

584=n[14+1.5n-1.5]

584= 14n+1.5n²-1.5n

584= 1.5n²+12.5n

1.5n²+12.5n-584

1.5n²-24n+36.5n-584

1.5n(n-16)+36.5(n-16)

(1.5n+36.5)(n-16)

**n-16=0

n=16

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