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3 years ago

Write an equation perpendicular to y = 3/4x that passes through the point(3,-3)

Mathematics

1 answer:

ryzh [129]3 years ago

5 0

Step-by-step explanation:

the slope perpendicular to y= ¾x is

-1 ÷ ¾ = -4/3

so the equation :

y-(-3)= -4/3(x-3)

y+3= -4/3x +4

y = -4/3x +4-3

y = -4/3x + 1

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3 years ago

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3 years ago

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2 years ago

True or false? An obtuse triangle cannot be similar to an acute triangle.

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Answer:

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3 years ago

Read 2 more answers

What are the domain and range of the inequality y < sqrt x+3+1

love history [14]

Given:

The inequality is:

$y$

To find:

The domain and range of the given inequality.

Solution:

We have,

$y$

The related equation is:

$y=\sqrt{x+3}+1$

This equation is defined if:

$x+3\geq 0$

$x\geq -3$

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3}\geq 0$

$\sqrt{x+3}+1\geq 0+1$

$y\geq 1$

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

Therefore, the correct option is A.

3 0

3 years ago